Answer:The relationship which is between bacteria and ungulates with the intestine is or good example of mutualism. Mutualism plays an important role in ecology. We can say that if we measure the exact fitness what we get as a benefit is a mutualistic relationship.example of a mutualistic relationship is that of the oxpecker (a kind of bird) and the rhinoceros or zebra. Oxpeckers land on rhinos or zebras and eat ticks and other parasites that live on their skin. The oxpeckers get food and the beasts get pest control.
Explanation:
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1) Chemical reaction:
2(CH₃COO)₃Fe + 3MgCrO₄ → Fe₂(CrO₄)₃ + 3(CH₃COO)₂Mg.
m((CH₃COO)₃Fe) = 15,0 g.
m(MgCrO₄) = 10,0 g.
n((CH₃COO)₃Fe) = m((CH₃COO)₃Fe) ÷ M((CH₃COO)₃Fe).
n((CH₃COO)₃Fe) = 15 g ÷ 233 g/mol.
n((CH₃COO)₃Fe) = 0,064 mol.
n(MgCrO₄) = m(MgCrO₄) ÷ M(MgCrO₄).
n(MgCrO₄) = 10 g ÷ 140,3 g/mol.
n(MgCrO₄) = 0,071 mol; limiting reagens.
From chemical reaction: n(MgCrO₄) : n((CH₃COO)₂Mg) = 3 : 3.
n((CH₃COO)₂Mg) = 0,071 mol.
m((CH₃COO)₂Mg) = 0,071 mol · 142,4 g/mol.
n((CH₃COO)₂Mg) = 10,11 g.
2) Chemical reaction:
2(CH₃COO)₃Fe + 3MgSO₄ → Fe₂(SO₄)₃ + 3(CH₃COO)₂Mg.
m((CH₃COO)₃Fe) = 15,0 g.
m(MgSO₄) = 15,0 g.
n((CH₃COO)₃Fe) = m((CH₃COO)₃Fe) ÷ M((CH₃COO)₃Fe).
n((CH₃COO)₃Fe) = 15 g ÷ 233 g/mol.
n((CH₃COO)₃Fe) = 0,064 mol; limiting ragens.
n(MgSO₄) = m(MgSO₄) ÷ M(MgSO₄).
n(MgSO₄) = 15 g ÷ 120,36 g/mol.
n(MgSO₄) = 0,125 mol; limiting reagens.
From chemical reaction: n(CH₃COO)₃Fe) : n((CH₃COO)₂Mg) = 2 : 3.
n((CH₃COO)₂Mg) = 0,064 mol · 3/2.
n((CH₃COO)₂Mg) = 0,096 mol.
m((CH₃COO)₂Mg) = 0,096 mol · 142,4 g/mol.
m((CH₃COO)₂Mg) = 13,7 g.
Answer:
80 ml
Explanation:
Moles to start = .04 L * .6 M/L = .024 moles
this is how much must be in the final dilution
.2 moles / liter * x liter = .024 moles
x = .024 / .2 = .12 liter final volume
start with . 040 then add .080 to get .12 liter
.080 liter = 80 ml
A formula unit of the nitrate salt of Q is Q(NO3)2.
<h3>What is IUPAC nomenclature?</h3>
The IUPAC nomenclature was put together by the international Union of Pure and applied chemistry in order to have a uniform way of naming compounds.
We shall now find the names of the compounds;
1) Na* and HPO4²- ; sodium hydrogen tetraoxophoshate V
2) Potassium cation and cyanide anion ; Potassium cyanide
3) Calcium cation and hypochlorite anion; Calcium oxochlorate I
Knowing that the valency of NO3^- is one and that the compound formed between Q and CO3²- has the formula QCO3 we can conclude that a formula unit of its nitrate salt is Q(NO3)2.
Learn more about IUPAC nomenclature:brainly.com/question/14379357
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Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune are all of the planets and then we have two asteroid belts then you have the sun the closest star and then you have all of the stars and Pluto if you consider that a planet still.