Answer:
x = 0.324 M s⁻¹
Explanation:
Equation for the reaction can be represented as:
2 NO(g) + Cl₂ (g) ⇄ 2NOCl (g)
Rate = K [NO]² [Cl₂]
Concentration = 
from the question; their number of moles are constant since the species are quite alike.
As such; if Concentration varies inversely proportional to the volume;
we have: Concentration ∝ 
Concentration = 
Similarly; the Rate can now be expressed as:
Rate = K [NO]² [Cl₂]
Rate =

Rate = 
We were also told that the in the reaction, the gaseous system has an initial volume of 3.00 L and rate of formation of 0.0120 Ms⁻¹
So we can have:
0.0120 = 
0.0120 =
-----Equation (1)
Now; the new rate of formation when the volume of the system decreased to 1.00 L can now be calculated as:
x = 
x = 1 ------- Equation (2)
Dividing equation (2) with equation (1); we have:
= 
= 
x = 0.0120 × 27
x = 0.324 M s⁻¹
∴ the new rate of formation of NOCl = 0.324 M s⁻¹
A conductor is distinguished from an insulator with the same number of atoms by the number of nearly free electrons.
<h3>What are conductors and insulators?</h3>
Whether an object is made of conductive or nonconductive material affects how it behaves once it has been charged. Electrons can move freely between particles when they are in conductors, which are substances. The charge can be transported across the whole surface of an object constructed of a conducting substance.
A charge is swiftly dispersed across the full surface of the object if it is applied to it at a specific point. The motion of the electrons causes the distribution of charge. A charged object will constantly disperse its charge until the overall repulsive interactions between surplus electrons are minimized because conductors allow electrons to be moved from particle to particle.
Insulators, as opposed to conductors, are substances that prevent electrons from freely moving from one atom or molecule to another.
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The complete question is:
"A conductor is distinguished from an insulator with the same number of atoms by the number of:
A. nearly free atoms
B. electrons
C. nearly free electrons
D. protons
E. molecules"
Answer:
0.218mol
Explanation:
Using Avogadro's law equation;
Va/na = Vb/nb
Where;
Va = volume of gas A
Vb = volume of gas B
na = number of moles of gas A
nb = number of moles of gas B
According to the information in this question,
na = 0.4mol
nb = x mol
Va = 220ml
Vb = 120ml
Using Va/na = Vb/nb
220/0.4 = 120/x
Cross multiply
0.4 × 120 = 220 × x
48 = 220x
x = 48/220
x = 0.218mol
Answer:b. Acetoacetate concentration increases.
Explanation: