The compounds that can be formed by using only the cations and anions found in the item above are as follows: (1) Ca3(CO2)2, Na3CO2, NaOH, Ca(OH)2
The last two in the given are in aqueous phase. We are then left with the first two choices. Ca3(CO2)2 is exhibits a phase that is in solid form.
Hence, the answer to the question is Ca3(CO2)2
Answer:
The answer is wave B, wave A
Explanation:
The closer the waves the higher the pitch. The higher the waves the louder it is.
Answer:
NaOH+HCl ----->NaCl+H2O
Explanation:
number mole NaOH = number mole NaOH
M -molarity, V - volume
M(NaOH)*V(NaOH) = M(HCl)*V(HCl)
M(NaOH)*40 ml = 0.2 M*50 ml
M(NaOH)=0.2 M*50 ml/40 ml=1/4 M=0.25 M NaOH
The question requires to balance the equation.
The equation is already balanced, so the answer is:
<span>Ca(s)+Br2(l)⟶CaBr2(s)
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</span><span>Explanation:
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</span><span>1) The phases are identified with a letter to the right of the compound or element:
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</span><span>So, for Ca, the phase is (s) which means solid.
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</span><span>For Br₂ (l) the phase is (l) which means liquid.
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</span><span>For CaBr₂(s) the phase is (s) which means solid.
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</span><span>2) The core work of balancing is make the number of atoms of each element on the reactants equal to the same number of atoms on the products side.
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</span><span>That is the law of conservation of mass applied to chemcial reactions.
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</span><span>3) So, you have to add coefficientes on the right place to make the number of atoms on the left side equal to the number of the same kind of atom on the right side.
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</span><span>In this table you can verify that the equation given is balanced:
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</span><span>atom left side right side
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</span><span>Ca 1 1
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</span><span>Br 2 2
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</span><span>So, you do not need to modify any coefficients.
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