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Tju [1.3M]
3 years ago
13

Number of electrons the atom my accept from another atom?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

Yes atoms can accept the electrons from another atom like

Chlorine accept electron from hydrogen.

Explanation:

You might be interested in
Which statement describes a similarity between conductors and insulators?
Ivanshal [37]

Answer:

They can both be used in an electric circuit.

Explanation:

Though conductors and insulators are very different from each other but still they have a similarity that "they can both be used in an electric circuit".

Conductors are the material that allows electricity to flow and insulators have high resistance and do not allow electricity to flow.

Both conductors and insulators are used in an electric circuit as conductor is used in wires, batteries and bulb to flow current while insulators are used in insulation of wire, switches, plugs and etc. Combination of them makes the circuit shock free.

Hence, the correct answer is "They can both be used in an electric circuit."

4 0
2 years ago
Which of the following is not a greenhouse gas
Vinil7 [7]
A- water. It’s the only one that isn’t a gas
4 0
3 years ago
How many grams of carbon dioxide are in 35.6 liters of co2
lina2011 [118]
The grams of carbon  dioxide  that are in 35.6 liters  of Co2 is calculates as below
calculate the  number of moles of CO2

At STP  1 mole  = 22.4 L

what  about  35.6 liters

=   1mole x 35.6  liters/ 22.4 liters = 1.589  moles

mass of CO2 =  moles x molar  mass of CO2

= 1.589 mol x 44 g/mol  =  69.92 grams
3 0
2 years ago
Please help fast thank yuo
Masteriza [31]

Answer:

what is your question tell may i can help you

7 0
2 years ago
Read 2 more answers
Will mark the brainiest later for correct answers! Please show work.
Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
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