Answer:
34.23 grams H2O.
Explanation:
1 Mole of HCl produces 1 mole of water
So 1.9 moles producers 1.9 moles of water
= (2*1.008 + 16) * 1.9
= 18.016 * 1.9
= 34.23 grams H2O.
Answer:
Explanation:
The first thing we need to know is that the amino acid of tyrosine has an aromatic ring within its structure.
Also, recall that aromatics hydrocarbons are considered to be unsaturated and non-polar.
So, since like dissolve like. Then, The non-polar character of tyrosine is enhanced by its aromatic ring. As a result, Tyrosine amino acid is much more soluble in less polar solvents like methanol and ethanol than in moderate highly polar water.
From the given information:
Since water is a very polar solvent, and tyrosine amino acid is not particularly polar, it is just barely soluble in it.
In addition to the aforementioned, peptides are strongly polar in nature. However, as the amount of tyrosine amino acids in a peptide increases, the region of the non-polar portion of the peptide increases (owing to the rise of the aromatic ring), and thus the non-polar value of the peptide will also rise. And this non-polar nature of peptide will make them more soluble in non-polar solvent and decrease its solubility in water (because water is polar in nature). And since peptides are non-polar, they would be more soluble in non-polar solvents and have less solubility in water.
Answer:
The acceleration is positive because they’re speeding up 4. An airplane touches down on the runway at 37m/s. After 8 seconds, the airplane has slowed to a velocity of 5 m/s.
Explanation:
Where, M is molarity (M or mol/L), n is number of moles (mol) and v is the volume of the solution (L).
The molarity of given glucose solution is 2.5 M.
Volume is 1.0 L
Hence
2.5 M = n/1.0 L
n = 2.5 mol
Hence, number of moles of glucose in 1.0 L of 2.5 M solution is 2.5 mol.
1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol
a. this reaction is exothermic as ΔH is -ve
b. the equilibrium will shift 2 the left if nitrogen gas is removed
c. the equilibrium shift 2 the right if the temperature is lowered
d. the equilibrium shift 2 the left if ammonia (NH3) is added
e. principle of thermodynamic potential or Gibbs energy is used to answer B-D