Question

An airplane touches down on the runway at 37 m/s after 8 seconds, the airplane has slowed to a velocity of 5 m/s. what is a plane's acceleration?​

Answer 1

Answer:

$\boxed {\boxed {\sf a= -4 \ m/s^2}}$

Explanation:

Acceleration is the rate at which an object changes its velocity. It is the change in velocity over the change in time.

$a= \frac{ \Delta v}{\Delta t}$

The change in velocity is the difference between the final velocity and the initial velocity.

• Δv= final velocity - initial velocity

The airplane touches down at 37 meters per second, the slows to 5 meters per second. The final is 5 m/s and the initial is 37 m/s.

• Δv= 5 m/s - 37 m/s= -32 m/s

The change in time is also how much time it took for the velocity to change. In this case, the change in time is 8 seconds.

Now we know the values for the variables:

• Δv= -32 m/s
• Δt= 8 s

Substitute the values into the formula.

$a= \frac{-32 \ m/s}{8 \ s}$

Divide.

$a= -4 \ m/s /s$

$a= -4 \ m/s^2$

The acceleration is -4 meters per square second. Since the acceleration is negative, the airplane is slowing down.

Answer 2

Answer:

The acceleration is positive because they’re speeding up 4. An airplane touches down on the runway at 37m/s. After 8 seconds, the airplane has slowed to a velocity of 5 m/s.

Explanation: