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ale4655 [162]
2 years ago
6

An airplane touches down on the runway at 37 m/s after 8 seconds, the airplane has slowed to a velocity of 5 m/s. what is a plan

e's acceleration?​
Chemistry
2 answers:
Maksim231197 [3]2 years ago
5 0

Answer:

\boxed {\boxed {\sf a= -4 \ m/s^2}}

Explanation:

Acceleration is the rate at which an object changes its velocity. It is the change in velocity over the change in time.

a= \frac{ \Delta v}{\Delta t}

The change in velocity is the difference between the final velocity and the initial velocity.

  • Δv= final velocity - initial velocity

The airplane touches down at 37 meters per second, the slows to 5 meters per second. The final is 5 m/s and the initial is 37 m/s.

  • Δv= 5 m/s - 37 m/s= -32 m/s

The change in time is also how much time it took for the velocity to change. In this case, the change in time is 8 seconds.

Now we know the values for the variables:

  • Δv= -32 m/s
  • Δt= 8 s

Substitute the values into the formula.

a= \frac{-32 \ m/s}{8 \ s}

Divide.

a= -4 \  m/s /s

a= -4 \ m/s^2

The acceleration is -4 meters per square second. Since the acceleration is negative, the airplane is slowing down.

Bezzdna [24]2 years ago
4 0

Answer:

The acceleration is positive because they’re speeding up 4. An airplane touches down on the runway at 37m/s. After 8 seconds, the airplane has slowed to a velocity of 5 m/s.

Explanation:

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