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monitta
3 years ago
13

An emulsifying agent is typically characterized by having ____. a. one polar end c. two polar ends b. one nonpolar end d. one po

lar end and one nonpolar end
Chemistry
1 answer:
tangare [24]3 years ago
4 0

Answer:

An emulsifying agent is typically characterized by having <u><em>d. one polar end and one nonpolar end.</em></u>

Explanation:

Emulsifiers are substances that have the ability to bind, for example, fats with those substances that have mostly water in their conformation. In other words, the emulsifier facilitates mixtures of two or more immiscible liquid substances.

This is because the molecules of an emulsifier are often lipophilic (attract oil) at one end and hydrophilic (attract water) at the other. In other words it consists of a polar (hydrophilic) head group and a non-polar (hydrophobic) tail.

<u><em>An emulsifying agent is typically characterized by having d. one polar end and one nonpolar end.</em></u>

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If the solvent level in the developing jar is deeper than the origin (spotting line) of the TLC plate, the solvent will dissolve the compounds into the solvent reservoir instead of allowing them to move up the plate by capillary action. Thus, you will not see spots after the plate is developed.

What is Thin Layer Chromatography (TLC)?

  • TLC is a simple, quick, and inexpensive procedure that gives the chemist a quick answer as to how many components are in a mixture.
  • TLC is also used to support the identity of a compound in a mixture when the Rf of a compound is compared with the Rf of a known compound.
  • A TLC plate is a sheet of glass, metal, or plastic which is coated with a thin layer of a solid adsorbent (usually silica or alumina). A small amount of the mixture to be analysed is spotted near the bottom of this plate.
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  • As the solvent moves past the spot that was applied, an equilibrium is established for each component of the mixture between the molecules of that component which are adsorbed on the solid and the molecules which are in solution.
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To learn more about TLC: brainly.com/question/13483325

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2 years ago
A fossil is found to have a 14 C 14C level of 70.0 70.0 % compared to living organisms. How old is the fossil?
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Answer:

The age of the fossil be 2.1987\times 10^{4} years.

Explanation:

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope  C-14 = x

N = mass of the parent isotope left after the time, (t)  = 70.0% of x=0.07x

t_{\frac{1}{2}} = half life of the isotope  C-14 = 5730 years

\lambda = rate constant

Let the age of the fossil be t.

Now put all the given values in this formula, we get  t :

0.07x=x\times e^{-(\frac{0.693}{5730 years})\times t}

t=2.1987\times 10^{4} years

The age of the fossil be 2.1987\times 10^{4} years.

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