Answer:
(A) 7.9 m/s^{2}
(B) 19 m/s
(C) 91 m
Explanation:
initial velocity (U) = 0 mph = 0 m/s
final velocity (V) = 85 mph = 85 x 0.447 = 38 m/s
initial time (ti) = 0 s
final time (t) = 4.8 s
(A) acceleration = 
= 
= 7.9 m/s^{2}
(B) average velocity = 
=
= 19 m/s
(C) distance travelled (S) = ut + 
= (0 x 4.8) + 
= 91 m
Answer:
Yes , i also need answer
Explanation:
n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center
Answer:
0.4752 oz.
Explanation:
Length = 1000 ft
Converting ft to inches,
12 in = 1 ft
1000 ft = 1000 * 12
= 12000 in
0.05082 in = 0.12908 cm
Mass = 19.8 lb
Converting lb to oz,
1 ounce = 0.0625 lb
1 lb = 1/0.0625 oz
19.8 lb = 1/0.0625 * 19.8
= 316.8 ounce
Since, 12000 in of copper wire weighs 316.8 ounces.
Therefore, 1 in will weigh = 316.8/12000
= 0.0264 oz
18 in = 0.0264 * 18
= 0.4752 oz.
