Answer:
for copper potential difference is 2.4871 ×
V
for silver potential difference is 2.1256 ×
V
Explanation:
given data
diameter D = 1.628 mm = 0.001628 m
current = 14.0 mA = 0.0140 A
length L = 2.15 m
to find out
potential difference
solution
we consider here
resistivity of silver = 1.47 ×
ohm-m
resistivity of copper = 1.72 ×
ohm-m
so we apply here resistance formula that is
Resistance = ρ × L / A ...............1
so here area A = πr² = π(0.001628 /2)² = 2.0816 ×
m²
for copper Resistance = ρ × L / A
Resistance = 1.72 ×
× 2.15 / 2.0816 × ![10^{-6}](https://tex.z-dn.net/?f=10%5E%7B-6%7D)
Resistance = 1.7765 ×
ohm
for silver Resistance = ρ × L / A
Resistance = 1.47 ×
× 2.15 / 2.0816 × ![10^{-6}](https://tex.z-dn.net/?f=10%5E%7B-6%7D)
Resistance = 1.5183 ×
ohm
so
potential difference is calculated as
for copper potential difference = current × resistance
potential difference = 0.0140 ×1.7765 × ![10^{-2}](https://tex.z-dn.net/?f=10%5E%7B-2%7D)
potential difference = 2.4871 ×
V
for silver potential difference = current × resistance
potential difference = 0.0140 × 1.5183 ×
potential difference = 2.1256 ×
V