Answer:
a) x = ⅔ d
, b) the charge must be negative, c) Q
Explanation:
a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing
∑ F = 0
-F₁₂ + F₂₃ = 0
F₁₂ = F₂₃
let's replace the values
k Q Q / r₁₂² = k Q 4Q / r₂₃²
Q² / r₁₂² = 4 Q² / r₂₃²
suppose charge 3 is placed at point x
r₁₂ = x
r₂₃ = d-x
we substitute
1 / x² = 4 / (d-x) 2
1 / x = 2 / (d-x)
x = 2 (x-d)
x = 2x -2d
3x = 2d
x = ⅔ d
b) The sign of the charge must be negative, to have an attractive charge on the two initial charges
c) Q
Answer:
it increases too as it bend away from the normal line
Answer:
D) 0.33 m/s² to the right
Explanation:
Apply Newton's second law. Take right to be positive and left to be negative.
∑F = ma
20 N − 5 N = (45 kg) a
a = 0.33 m/s²
The couch accelerates at 0.33 m/s² to the right.
Answer:
the resulting angular speed after she pulls her hand inwards in (rad/s) is 27.02 rad/s
Explanation:
Given that :
the initial angular speed 
Initial rotational inertia 
Final angular speed 
Final rotational inertia 
According to conservation of momentum :
Initial momentum = final momentum
To rad/s ; we have:
Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s
