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kondor19780726 [428]
3 years ago
14

You are walking on a moving walkway in the airport. The length of the walkway is 59.1 m. If your velocity relative to the walkwa

y is 2.35 m/s, and the walkway moves with a velocity of 1.85 m/s, how long will it take you to reach the other end of the walkway
Physics
1 answer:
MrMuchimi3 years ago
8 0

Answer:

14.1seconds approx

Explanation:

Given data

Distance= 59.1m

Your velocity= 2.35m/s

Walkway velocity= 1.85m/s

Total velocity= 2.35+1.85= 4.2m/s

We know that

Velocity= distance/time

time= distance/velocity

substitute

time= 59.1/4.2

time= 14.07

time=14.1seconds approx

Hence the time is 14.1seconds approx

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A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.62 m/s2 for t1 = 20 s. At that point the
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Total displacement of the car: 405 m

Explanation:

The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation

s_1=ut_1+\frac{1}{2}a_1 t_1^2

where:

u = 0 is the initial velocity (the car starts from rest)

t_1 = 20 s is the time elapsed in the 1st part

a_1=1.62 m/s^2 is the acceleration of the car in the 1st part

s_1 is the displacement of the car in the 1st part

Solving for s_1,

s_1=0+\frac{1}{2}(1.62)(20)^2=324 m

We can also find the velocity of the car after these 20 seconds using the equation:

v_1 = u +a_1 t_1 = 0 + (1.62)(20)=32.4 m/s

Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:

s_2 = (\frac{v_1 + v_2}{2})t_2

where:

v_1=32.4 m/s is the initial velocity at the beginning of the 2nd phase

v_2=0 is the final velocity (the car comes to a stop)

t_2=5 s is the time elapsed in the 2nd phase

Substituting,

s_2=\frac{32.4+0}{2}(5)=81 m

So, the total displacement of the car is

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Learn more about accelerated motion:

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40 j, 80j.

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Answer:

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Explanation:

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Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

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