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4 years ago

Write a chemical equation representing the first ionization energy for lithium. use e− as the symbol for an electron.

Chemistry

2 answers:

horsena [70]4 years ago

7 0

$\boxed{{\text{Li}} \to {\text{L}}{{\text{i}}^ + } + {{\text{e}}^ - }}$ is the chemical equation that represents the first ionization energy of lithium.

Further Explanation:

Ionization energy is the amount of energy that is required to remove the most loosely bound valence electrons from the isolated neutral gaseous atom. It is denoted by IE. The value of IE is related to the ease of removing the outermost valence electrons. If these electrons are removed so easily, small ionization energy is required and vice-versa. It is inversely proportional to the size of the atom.

Ionization energy is further represented as first ionization, second ionization and so on. When the first electron is removed from a neutral, isolated gaseous atom, the energy needed for the purpose is known as the first ionization energy, written as ${\text{I}}{{\text{E}}_{\text{1}}}$ . Similarly, when the second electron is removed from the positively charged species (cation), the ionization energy is called the second ionization energy $\left( {{\text{I}}{{\text{E}}_2}} \right)$ and so on.

The atomic number of lithium is 3. So its electronic configuration is $1{s^2}2{s^1}$ . Its outermost electron is present in 2<em>s</em> orbital. The amount of energy required to remove this electron of lithium atom is known as the first ionization energy of lithium.

The equation that represents the first ionization of lithium is ${\text{Li}} \to {\text{L}}{{\text{i}}^ + } + {{\text{e}}^ - }$ .

Learn more:

1. The subatomic particle with the least mass: brainly.com/question/2224691

2. Number of carbon atoms in 1.3-carat diamond: brainly.com/question/4235993

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Periodic classification of elements

Keywords: first ionization energy, lithium, electronic configuration, atomic number, electron, neutral, isolated, gaseous atom, IE1., equation, size of the atom.

just olya [345]4 years ago

4 0

The chemical equation representing the first ionization energy for lithium is given by;

Li → Li + e-

<h2>Further Explanation; </h2><h3>Ionization energy</h3>

Ionization energy is the energy required to remove outermost electrons from the outermost energy level. Energy is required to remove an electron from an atom.
The closer an electron is to the nucleus the more energy is required, since the electron is more tightly bound to the atom thus making it more difficult to remove, hence higher ionization energy.
Ionization energy increases across the periods and decreases down the group from top to bottom.
Additionally, the ionization energy increases with subsequent removal of a second or a third electron.

<h3>First ionization energy </h3>

This is the energy required to remove the first electron from the outermost energy level of an atom.
Energy needed to remove the second electron to form a divalent cation is called the second ionization energy.

<h3>Trends in ionization energy </h3><h3>1. Down the group(top to bottom)</h3>

Ionization energy decreases down the groups in the periodic table from top to bottom.
It is because as you move down the group the number of energy levels increases making the outermost electrons get further from the nucleus reducing the strength of attraction to the nucleus.
This means less energy will be required compared to an atoms of elements at the top of the groups.

<h3>2. Across the period (left to right)</h3>

Ionization energy increases across the period from left to right.
This can be explained by an increase in nuclear energy as extra protons are added to the nucleus across the period increasing the strength of attraction of electrons to the nucleus.
Consequently, more energy is needed to remove electrons from the nucleus.

Keywords: Ionization energy, periodic table, energy levels, electrons

<h3>Learn more about</h3>

Ionization energy: brainly.com/question/1971327
Trend in ionization energy: brainly.com/question/1971327
First ionization energy: brainly.com/question/1971327

Level: High school

Subject: Chemistry

Topic: Periodic table and chemical families

Sub-topic: Ionization energy

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Answer:- The volume of copper is 280 mL.

Solution:- Density and mass of copper metal are given and it asks to calculate the volume of it.

Density is directly proportional to mass and inversely proportional to the volume. The density formula is:

$D=\frac{M}{V}$

where D stands for density, M stands for mass and V stands for volume.

Since, the problem asks to calculate the volume, let's rearrange the formula for volume.

$V=\frac{M}{D}$

The given density is 8.9 grams per mL and the mass is 2.5 kg. We need to convert the mass unit from kg to g so that the g unit could be canceled while calculating volume.

The conversion factor is, 1kg = 1000g

$2.5kg(\frac{1000g}{1kg})$

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3 years ago

At elevated temperatures, methylisonitrile (CH3NC) converts to acetonitrile (CH3CN): CH3NC(g) --> CH3CN(g) At the start of th

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Answer:

A. 3.7 x 10⁻³

Explanation:

In the beginning of the reaction there are 0.200 moles of reactant. After 25 minutes, remain 0.108 moles. That means the moles that wer descomposed are:

0.200 moles - 0.108 moles = 0.092 moles of reactant were descomposed.

That descomposition occurs in 25 minutes. The average rate of descomposition in moles / minute are:

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4 years ago

What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?

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Answer:

$\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}$

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

$molarity = \frac {moles}{liters}$

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

$\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}$

Multiply by the given number of grams.

$78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}$

Flip the fraction and divide.

$78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}$

$\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6$

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

$\frac {1 \ L }{ 1000 \ mL}$

Multiply by 2500 mL.

$2500 \ mL* \frac {1 \ L }{ 1000 \ mL}$

$2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L$

3. Calculate Molarity

Finally, divide the moles by the liters.

$molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}$

$molarity = 0.173183241191 \ mol \ C_6H_12O_6/L$

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

$molarity \approx 0.17 \ mol \ C_6H_12O_6 /L$

1 mole per liter is also equal to 1 M.

$molarity = 0.17 \ M \ C_6H_12O_6$

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The hydrogen model of Neil Bohr dealt with the quantum energy emission when electron excite from higher energy level to lower energy level. He also stated that there is a relationship between the outer shell and the chemical properties of elements.

So, the second option that is the charge of an electron is not contributed by Bohr as it was contributed by Millikan.

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3 years ago

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mars1129 [50]

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