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Pepsi [2]
3 years ago
15

Identify the contents of the following mixtures. Select all that apply. Each circle is an atom. Different colors are used for di

fferent types of atoms. Indicate atoms only for atoms not bound to other atoms. Please remember that the elemental form of some materials is simply the atom itself.
Chemistry
1 answer:
marusya05 [52]3 years ago
3 0

Answer:

What’s the question

Explanation:

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What is the atomic mass of an element that has 6 protons, 7 neutrons, and 6 electrons?
GREYUIT [131]

Answer:

13

Explanation:

proton plus neutron equal to atomic mass

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Describe the distribution of mass within an atom
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The nuclei of most atoms also contain neutrons . The masses of subatomic particles are very tiny. ... Since the nucleus contains protons and neutrons, most of the mass of an atom is concentrated in its nucleus. Protons and electrons have electrical charges that are equal and opposite.

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What sample has particles with the lowest average kinetic energy
makvit [3.9K]

The sample with the lowest AVERAGE kinetic energy is
the coolest one.

The sample with the lowest TOTAL kinetic energy depends on
not only the temperature of the samples, but also on their size,
since each molecule in the sample has kinetic energy.

5 0
3 years ago
100 POINTS! Final Honor Activity Question
castortr0y [4]

The change in temperature had the greatest effect at changing the volume of the balloon.

<h3>What are the gas laws?</h3>

The gas laws are used to describe the parameters that has to do with gases.

Given that;

P1 = 98.5 kPa

T1 = 18oC or 291 K

V1 =  74.0 dm3

P2 =  7.0 kPa

V2 = ?

T2 = 18oC or 291 K

P1V1/T1 = P2V2/T2

P1V1T2 =P2V2T1

V2= P1V1T2/P2T1

V2 =  98.5 kPa *  74.0 dm3 * 291 K/ 7.0 kPa * 291 K

V2 = 1041.3 dm3

When;

V1 = 1041.3 dm3

T1 = 291 K

V2 = ?

T2 = 80oC or 353 K

V1/T1 = V2/T2

V1T2 = V2T1

V2 = V1T2/T1

V2 = 1041.3 dm3 * 353 K/291 K

V2 = 1263 dm3

The change in temperature had the greatest effect at changing the volume of the balloon.

Given that

V1 =  100 cm^3

T1 = 273 K

P1 = 1.01 * 10^5 Pa

V2 = ?

P2 =  3.00 x 10^-4 Pa

T2 = -180oC or 255 K

V2= P1V1T2/P2T1

V2 =  1.01 * 10^5 Pa * 100 cm^3 * 255 K / 3.00 x 10^-4 Pa * 273 K

V2 = 3.14 * 10^10 cm^3

Learn more about gas laws:brainly.com/question/12669509

#SPJ1

7 0
2 years ago
The acid-dissociation constant at 25.0 °c for hypochlorous acid (hclo) is 3.0 ⋅ 10−8. at equilibrium, the molarity of h3o+ in a
maks197457 [2]

Hypochlorous acid is a weak acid. The K_{a} value for the dissociation of HOCl is 3.0 * 10^{-8}


3 0
3 years ago
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