Answer:
The answer to the question is
The star’s approximate radial velocity is 68.52 km/s
Explanation:
To solve the
The formula is
where
= velocity of the star
λ = Star's spectrum wavelength = 656.45 nm
= Rest wavelength = 656.30 nm
c = Speed of light = 299 792 458 m / s
Therefore we have
or = 68518.7699 m/s or 68.52 km/s
The TLC analysis is aimed to verify the completion and the product of the reaction. potassium permanganate is then added to the TLC plate to detect the existence of double bond in the final product. Potassium permanganate reacts with the double bond and makes the spot yellow-brown.
Electrophilic addition is an exothermic reaction, in which a pi bond is turned into a sigma bond. The double bond in the alkene acts as a nucleophile. Halogens, halogen acids , hypohalous acids, sulphonic acid and water can be used as the electrophilic reagent. In this experiment, bromination of cholesterol is performed. The electrophilic attack of Br2generates acyclic bromonium ion. The addition gives a trans stereochemistry to the bromonium ion. As the Br-attacks the most substituted carbon in anti-periplanar fashion by SN2reaction, it would result in the inversion of configuration at that specific carbon.
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Carbon can form four bonds with other molecules/elements. It is the most important element in Organic Chemistry.
It’s soluble in NaOH, NaH
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
<em>Volume Methane:</em>
3600s * (0.25L / s) = 900L Methane
<em>Moles methane:</em>
PV = nRT; PV / RT = n
<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
<em>Mass methane:</em>
40.18 moles * (16g/mol) =
<h3>643g of methane will there be in the room</h3>