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3 years ago

Electroplating is a method of rust prevension

1 answer:

6 0

This is true. coating a ferrous material with a thin layer of a non-ferrous material is an effective method of preventing ferrous oxidation in the base material.

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If the pressure of 200 cm cube of a gas is half at constant temperature.what will be the new volume

Debora [2.8K]

Answer:

hbjeofjwwkjjhhwhhyuhcuh

Explanation:

bjsdhoooiiifckuvghvvr

3 0

2 years ago

how many atoms of phosphorous are in 4.90 mol of copper(ii) phosphate? the formula for copper(ii) phosphate is Cu3(PO4)2.

Karolina [17]

Answer:

$\boxed{5.90 \times 10^{24}}$

Explanation:

Step 1. Calculate the formula units of Cu₃(PO₄)₂

$\text{4.90 mol Cu$_{3}$(PO$_{4}$)$_{2}$} \times \dfrac{6.022 \times 10^{23} \text{ formula units}}{\text{1 mol Cu$_{3}$(PO$_{4}$)$_{2}$}}\\\\=\text{2.951 $\times$ 10$^{24}$ formula units Cu$_{3}$(PO$_{4}$)$_{2}$}$

Step 2. Calculate the atoms of P

$\text{Atoms of P}\\\\=\text{2.951 $\times$ 10$^{24}$ formula units Cu$_{3}$(PO$_{4}$)$_{2}$} \times \dfrac{ \text{2 atoms P}}{\text{1 formula unit Cu$_{3}$(PO$_{4}$)$_{2}$}}\\\\= \boxed{5.90 \times 10^{24} \text{ atoms P}}$

8 0

3 years ago

Which measurement describes the pressure of a gas?

pychu [463]

Answer:

725 mmHg

Explanation:

mmHg is a sort of unit to determine pressure.

g/L, is a unit for density

2.5L is a value for volume

315K is a value for Asbolute T° (Kelvin grade)

3 0

3 years ago

Which of the following statements correctly describes the substance with the formula ki?

anzhelika [568]

The correct answer is a

3 0

3 years ago

Read 2 more answers

A 20-kg bicycle carrying a 50-kg girl is traveling at a speed of 8 m/s. What is the kinetic energy of the girl

finlep [7]

Answer:

The answer to your question is Ke = 2240 J

Explanation:

Data

mass of the object = 20 kg

mass of the girl = 50 kg

speed = 8 m/s

Kinetic energy = Ke = ?

Formula

Ke = 1/2 mv²

Process

Kinetic energy is due to the movement of an object.

1.- Calculate the total mass

Total mass = 20 + 50 = 70 kg

2.- Substitution

Ke = 1/2(70)(8)²

3.- Simplification

Ke = 1/2(4480)

4.- Result

Ke = 2240 J

6 0

3 years ago