Answer:
The kinetic energy of the two curling stones is 320 J
Explanation:
Given;
mass of the first curling stone, m₁ = 20 kg
velocity of the first curling stone, v₁ = 4 m/s
velocity of the second curling stone, v₂ = - 4m/s
assuming the second curling stone to have equal mass with the first stone = 20 kg
The kinetic energy of the first curling stone is given by;
K.E₁ = ¹/₂m₁v₁²
K.E₁ = ¹/₂(20)(4)²
K.E₁ = 160 J
The kinetic energy of the second stone is given by;
K.E₂ = ¹/₂m₂v₂²
K.E₂ = ¹/₂ (20) (-4)²
K.E₂ = 160 J
Thus, the kinetic energy of the two curling stones is given by;
K.E = K.E₁ + K.E₂
K.E = 160 J + 160 J
K.E = 320 J
Therefore, the kinetic energy of the two curling stones is 320 J
Answer:
Explanation:
Do a quick conversion: 1 grams H3PO4 = 0.010204583427424 mole using the molecular. How many grams H3PO4 in 1 mol? You can view more details on each measurement unit: molecular weight of H3PO4 or mol This. The formula weight is simply the weight in atomic mass units of all the atoms in a given formula.
Answer:
16.7 mL
Explanation:
Convert 250 mL to L.
250 mL = 0.250 L
Calculate the amount of moles of NaOH in 250 mL of 0.300 M NaOH.
0.250 L × 0.300 M = 0.075 mol
Using this amount of moles, you need to find out what volume of 4.50 M will give you that many moles. You can do this by dividing the amount of moles by the molarity.
(0.075 mol)/(4.50 M) = 0.0167 L
Convert from L to mL.
0.0167 L = 16.7 mL
Hey mate!
Taxonomy is the <span>study of classification of organisms. Therefore, your answer is A.
Hope this helps!</span>
