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laiz [17]
2 years ago
15

What is the percentage of 28,24,29,18,13,43,38,14,49,32 with a fuel efficiency less than 32mpg

Mathematics
1 answer:
Anni [7]2 years ago
7 0

The percentage of these cars with a fuel efficiency less than 32 mpg is; 90%

<h3>How to Find the percentage?</h3>

We are can the efficiencies of 10 cars in mpg.

Now, among the 10 cars, the number of cars that have an mpg less than 32 mpg are 9 cars.

Thus, percentage of these cars with a fuel efficiency less than 32 mpg is;

Percentage = 9/10 * 100%

Percentage = 90%

Complete question is;

Here are the fuel efficiencies (in mpg) of 10 new cars; 28, 24, 29, 18, 13, 43, 38, 14, 49, 32. What is the percentage of these cars with a fuel efficiency less than 32 mpg?

Read more about Percentage at; brainly.com/question/843074

#SPJ1

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lyudmila [28]

Answer:

8

Step-by-step explanation:

A2+B2=C2

A2+15squared=17squared

A2+225=289

289-225=64

A2=64

64 squared is 8

7 0
3 years ago
Layla emptied out her change jar to buy a new binder for school. She found 147 coins consisting of dimes and nickels that totale
den301095 [7]

Answer:

d + n = 147

0.10d + 0.05n = 11.65

d = 86, n = 61

Step-by-step explanation:

Let

Number of dimes = d

Number of nickels = n

Total coins = 147

Total value = $11.65

d + n = 147 (1)

0.10d + 0.05n = 11.65 (2)

From (1)

d = 147 - n

Substitute d = 147 - n into

0.10d + 0.05n = 11.65

0.10(147 - n) + 0.05n = 11.65

14.7 - 0.10n + 0.05n = 11.65

- 0.10n + 0.05n = 11.65 - 14.7

-0.05n = -3.05

n = -3.05 / -0.05

= 61

n = 61

Substitute n = 61 into

d + n = 147

d + 61 = 147

d = 147 - 61

d = 86

6 0
3 years ago
Can anyone help me out on this question
statuscvo [17]

12/4(-1)+2=

12/-4+2 =

12/-2 =

-6

8 0
3 years ago
Read 2 more answers
Does a set of rational numbers include the set of integers
NeX [460]
Yes, a set of rational numbers include the set of integers
3 0
4 years ago
The ages of three siblings are consecutive integers. The sum of their ages is 42. Calculate their ages. *
stealth61 [152]

Answer:

13, 14, 15

Step-by-step explanation:

Let x = age of one of the siblings

Since the age of the siblings are consecutive integers, the age of the next sibling would be x + 1 and the age of the third sibling would be x + 2

x +( x +1) + (x +2) = 42

3x + 3 = 42

collect like terms and solve for x

x = 13

The age of the first sibling is 13

The age of the second sibling is x + 1 = 13 + 1 = 14

The age of the third sibling is x + 2 = 13 + 2 = 15

8 0
3 years ago
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