Distance is 33 km, displacement is 3 km east
Explanation:
- Distance is a scalar quantity equal to the total length of the path covered by an object during its motion, regardless of its direction.
- Displacement is a vector connecting the starting position of motion of an object to its final position. It is a vector quantity, therefore it has both magnitude and direction.
In this problem, the motion of the person is:
12 km north
6 km east
12 km south
3 km west
Therefore, the distance is:
The displacement instead can be calculated by comparing the final position with the initial position. We notice that:
- the person goes 12 km north and 12 km south, so he didn't move in the north-direction
- The person goes 6 km east and 3 km west, so his final position is 3 km east
Therefore, the displacement is 3 km east.
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La longitud del faldón de la rampa es de 5.4 m.
La pendiente expresada en porcentaje sigue la siguiente ecuación:
(1)
Donde:
- y es la elevacion de la rampa (faldón)
- x es la longitud de la ramapa (20 m)
Sabemos que la pendiente es de 27%. Por lo tanto, usando la ecuación 1, despejamos y.
La longitud del faldón es 5.4 m
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Answer:
Explanation:
Polarization In this case angle of incidence is not equal to angle of polarization, hence reflected light is partially polarized and transmitted light is also partially polarized. by reflection is explained by Brewster's law,
According to this when unpolarized light incident on glass plate at an angle is called as angle of polarizing the reflected light is plane polarized, and transmitted light is partially polarized. The plane of vibration of polarized light is having plane of vibrations perpendicular to plane of incidence.
Venus shares a similar size, surface composition, and has an atmosphere with a complex weather system. Venus is different from Earth because it spins the opposite direction of Earth and it’s rotation is very slow.
Answer:
v₁ = 3.5 m/s
v₂ = 6.4 m/s
Explanation:
We have the following data:
m₁ = mass of trailing car = 400 kg
m₂ = mass of leading car = 400 kg
u₁ = initial speed of trailing car = 6.4 m/s
u₂ = initial speed of leading car = 3.5 m/s
v₁ = final speed of trailing car = ?
v₂ = final speed of leading car = ?
The final speed of the leading car is given by the following formula:
<u>v₂ = 6.4 m/s</u>
The final speed of the leading car is given by the following formula:
<u>v₁ = 3.5 m/s</u>
