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BartSMP [9]
3 years ago
5

Derive Isothermal process through ideal gas.(anyone plzz!!)​

Physics
1 answer:
zysi [14]3 years ago
8 0

Answer:

Hey, bro here is the explanation....

Explanation:

Hope it helps...

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Convert the Celsius temperature of the surface of the sun, which is
Ghella [55]
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The conversion factor is:

F = C *  \frac{9}{5} + 32

So, if we plug in the numbers, we get:
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5 0
3 years ago
A point charge is located at the center of a thin spherical conducting shell of inner and outer radii r1 and r2, respectively. A
nadya68 [22]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  point charge is  Q_z = -0.0912 \ \mu C

The inner shell is  Q_t = 0.4168 \ \mu C

The outer shell is  Q_w = -0.6514 \ \mu C

Explanation:

From the question we are told that

    The inner radius of thin first spherical conducting shell is  r_1

    The outer radius of thin first spherical conducting shell is  r_2

    The inner radius of second thin spherical conducting shell is R_1

    The outer radius of second thin spherical conducting shell is R_2

     The magnetic flux for different region is  \phi =  -10.3 *10^3 N\cdot m^2 /C \ for  \ r < r_1

    The magnetic flux for first shell is \phi = 36 * 10^3 N \cdot m^2 /C \ for  \ r_2 < r

     The magnetic flux for second shell is \phi = -36 * 10^3 N \cdot m^2 /C \ for \  r

The magnitude of the point charge is mathematically represented as

                Q_z =  \ \phi_z * \epsilon _o

               Q_z =  -10.3*10^{3} * 8.85 *10^{-12}

               Q_z =  -9.115*10^{-8} \ C

               Q_z = -0.0912 \ \mu C

Considering the inner shell

        Q_a  = \phi_a * \epsilon _o

=>    Q_a  = 36 .8 * 10^3 * 8.85*10^{-12}

      Q_a  = 32.56*10^{-8} \ C

       Q_a  =0.326} \ \mu C

Charge on the inner shell is

       Q_t  =  Q_a  - Q_z

                    Q_t = 0.326} \ \mu   -   ( -0.0912 \ \mu)

                      Q_t = 0.4168 \ \mu C

Considering the outer  shell

     Q_y  =  \phi_y * \epsilon_o

=>    Q_y  =  -36.8 *10^{3} *  8.85*10^{-12}

        Q_y  = -32.56*10^{-8} \ C

        Q_y  = - 0.326} \ \mu C

Charge on the outer shell is

      Q_w =  Q_y - Q_z

      Q_w =-  0.326} \ \mu   -   ( -0.0912 \ \mu)

       Q_w = -0.6514 \ \mu C

 

5 0
3 years ago
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