Answer:
F = k q1 q2 / r^2
r^2 = k q1 q2 / F = 9E9 * 4E-5 * 10.8E-5 / 4
r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2
r = 3.12 m
No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels
E = hf
E = 6.63* 10 ⁻³⁴ * 7.24* 10¹⁴
<span>E = 4.80012 × 10⁻¹⁹ J</span>
I sorry but I don’t know if you are doing virtual just keep trying and never give up
