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ASHA 777 [7]
1 year ago
9

An object with a density of 250 kg/m3 floats on water. what portion of the object is submerged?

Physics
1 answer:
lbvjy [14]1 year ago
6 0

The portion of the object submerged in water is determined as 0.25.

<h3>Fraction of the object submerged in water</h3>

The fraction of the object submerged in water is calculated as follows;

S.G =  (density of object) / (density of water)

where;

  • S.G is specific gravity

S.G = (250 kgm⁻³) / (1000 kgm⁻³)

S.G = 0.25 = ¹/₄

Thus, the portion of the object submerged in water is determined as 0.25.

Learn more about density here: brainly.com/question/1354972

#SPJ1

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