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ASHA 777 [7]
1 year ago
9

An object with a density of 250 kg/m3 floats on water. what portion of the object is submerged?

Physics
1 answer:
lbvjy [14]1 year ago
6 0

The portion of the object submerged in water is determined as 0.25.

<h3>Fraction of the object submerged in water</h3>

The fraction of the object submerged in water is calculated as follows;

S.G =  (density of object) / (density of water)

where;

  • S.G is specific gravity

S.G = (250 kgm⁻³) / (1000 kgm⁻³)

S.G = 0.25 = ¹/₄

Thus, the portion of the object submerged in water is determined as 0.25.

Learn more about density here: brainly.com/question/1354972

#SPJ1

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Answer:

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Explanation:

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An 85-kg refrigerator is located on the 70th floor of a skyscraper (4km above the ground ) what is the potential energy
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h is the height = 4 km = 4000 meters

Substitute in the above equation to get the potential energy as follows:
Potential energy = 85*9.8*4000 = 3332000 joules
7 0
3 years ago
List five examples from daily life in which you see periodic motion caused by a spring or cord.
dmitriy555 [2]

car suspension

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4 0
3 years ago
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What is the acceleration of a boy on a skateboard if the net force on the boy is 15 N? The total mass of the boy and the skatebo
Stels [109]
                                 Force = (mass) x (acceleration)

If the full 15N is pointing parallel to the ground,
then

                                   15 N  =  (58 kg) x (acceleration).

Divide each side
by  58 kg:                   Acceleration = 15 N / 58 kg

                                                         = (15 kg-m/s²) / (58 kg)

                                                         = (15/58) (kg-m/kg-s²)

                                                         =  0.26 m/s² .
7 0
3 years ago
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A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N
mart [117]

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force(F_{A}) and the kinetic frictional force(F_{R}). i.e

F = F_{A} - F_{R}    -----------------(i)

Note that;

F_{R} = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = F_{A} - μmg        -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

F_{A} = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

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3 years ago
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