Answer: I think its A a mole burrows underground
Explanation:
Answer:
The parent's genotypes are:
Ddpp - tall, white parent
ddPp - dwarf, purple parent.
Explanation:
This question involves two different genes coding for height and flower color in pea plants. The alleles for tallness (D) and purple color (P) are dominant over the alleles for dwarfness (d) and white color (p) respectively.
According to this question, a tall plant with white flowers is crossed with a dwarf plant with purple flowers to produce the following proportion of offsprings: 1/4 tall purple, 1/4 tall white, 1/4 dwarf purple, and 1/4 dwarf white.
Since some of the offsprings contain recessive alleles for both or either genes, the dominant traits of the parent is controlled by an heterozygous genotype. This means that the tall plant with white flowers has a genotype: Ddpp while the dwarf plant with purple flowers has the genotype: ddPp. In a cross between Ddpp × ddPp, 1/4 of each combination of alleles is produced in the offsprings (see punnet square in the attachment).
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
Answer:
<u>Repeat a behaviour.</u>
Explanation:
When we adopt a new behaviour, a neural pathway is created and it gets stronger when we repeat until it become a new normal behaviour or a habit. When a message travels in a same neuronal pathway again and again, the brain begin to transmit it even more faster and these behaviours become automatic.
Explanation:
hope it's help you ok have a good day
