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a_sh-v [17]
2 years ago
10

Which substance do you expect to be most soluble in water? Group of answer choices Methane, CH4 Nitrogen, N2 Ammonia, NH3 Carbon

dioxide, CO2
Chemistry
1 answer:
sdas [7]2 years ago
6 0

Answer:

Ammonia, NH3

Explanation:

The water is a polar solvent, which means that it has a dipole moment different from 0. The polar solvents solubles polar solutes.

The polarity can be found by the VSPER theory, where the bonds and the lone pairs of electrons at the central atom are the most distance possible. If the bonds are done by elements with close electronegativity, it's nonpolar, if it's done with elements with different electronegativities, it's polar.

The polar moment of the bonds are vectors if the sum of it is 0, the molecule is nonpolar, if it's different from 0, the molecule is polar.

Methane, CH4, has a tetrahedral geometry, and the bonds of C-H are nonpolar, thus it is a nonpolar molecule.

Nitrogen, N2, has a linear geometry and is nonpolar (bonds with

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Consider the following reaction between calcium oxide and carbon dioxide: CaO(s)+CO2(g)→CaCO3(s) A chemist allows 14.4 g of CaO
sweet-ann [11.9K]

Answer:

Theoretical yield =26.03 g

Percent yield = 87%

Limiting reactant = CaO

Explanation:

Given data:

Mass of CaO = 14.4 g

Mass of CO₂ = 13.8 g

Actual yield of CaCO₃ = 22.6 g

Theoretical yield = ?

Percent yield = ?

Limiting reactant = ?

Solution:

Chemical equation:

CaO + CO₂   → CaCO₃

Number of moles of CaO:

Number of moles  = Mass /molar mass

Number of moles = 14.4 g / 56.1 g/mol

Number of moles  = 0.26 mol

Number of moles of CO₂:

Number of moles = Mass /molar mass

Number of moles = 13.8 g / 44 g/mol

Number of moles = 0.31 mol

Now we will compare the moles of CO₂ and CaO with CaCO₃ .

                  CO₂         :                CaCO₃  

                  1               :                 1

                 0.31           :              0.31

                CaO           :               CaCO₃  

                 1                :                 1

                 0.26         :              0.26

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

Mass of CaCO₃: Theoretical yield

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ =0.26 mol × 100.1 g/mol

Mass of CaCO₃ =  26.03 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 22.6 g/ 26.03 g × 100

Percent yield = 0.87× 100

Percent yield = 87%

Limiting reactant:

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

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