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a_sh-v [17]
3 years ago
10

Which substance do you expect to be most soluble in water? Group of answer choices Methane, CH4 Nitrogen, N2 Ammonia, NH3 Carbon

dioxide, CO2
Chemistry
1 answer:
sdas [7]3 years ago
6 0

Answer:

Ammonia, NH3

Explanation:

The water is a polar solvent, which means that it has a dipole moment different from 0. The polar solvents solubles polar solutes.

The polarity can be found by the VSPER theory, where the bonds and the lone pairs of electrons at the central atom are the most distance possible. If the bonds are done by elements with close electronegativity, it's nonpolar, if it's done with elements with different electronegativities, it's polar.

The polar moment of the bonds are vectors if the sum of it is 0, the molecule is nonpolar, if it's different from 0, the molecule is polar.

Methane, CH4, has a tetrahedral geometry, and the bonds of C-H are nonpolar, thus it is a nonpolar molecule.

Nitrogen, N2, has a linear geometry and is nonpolar (bonds with

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5 0
3 years ago
how many grams of antifreeze would be required per 500 g of water to prevent the water from feezing at a temperature of -39° C​
andrezito [222]

Answer:

333.7g of antifreeze

Explanation:

Freezing point depression in a solvent (In this case, water) occurs by the addition of a solute. The law is:

ΔT = Kf × m × i

Where:

ΔT is change in temperature (0°C - -20°C = 20°C)

Kf is freezing point depression constant (1.86°C / m)

m is molality of solution (moles solute / 0.5 kg solvent -500g water-)

i is Van't Hoff factor (1, assuming antifreeze is ethylene glycol -C₂H₄(OH)₂)

Replacing:

20°C = 1.86°C / m  × moles solute / 0.5 kg solvent × 1

5.376 = moles solute

As molar mass of ethylene glycol is 62.07g/mol:

5.376 moles × (62.07g / 1mol) = <em>333.7g of antifreeze</em>.

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3 years ago
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