What is the name of Pb(NO3)2? Explain how you determined the bond type and the steps you used to determine the naming convention
1 answer:
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Answer : The formula that represent hydrogen ions in an aqueous solution is,
Explanation :
As we know that the formula of water is, .
In an aqueous solution, it dissociates to give hydrogen ion and hydroxide ion.
The dissociation reaction is:
The formula of hydrogen ion is,
The formula of hydroxide ion is,
Hence, the formula that represent hydrogen ions in an aqueous solution is,
Answer 1) : According to the complete question attached in the answer,
The radial wave function which is denoted by shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.
Also, the radial probability distribution curve denoted as shown in blue color is observed to touch zero, and shows the place of radial node.
Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by <em>'n'</em>.
It is observed that for any atomic orbital, the total number of nodes will be n-1 .
Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.
Hence, there will be only radial nodes, which is
(n−1 = total number of radial nodes in s orbitals)
According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)
This represents the 5s orbital.
Answer 2) The radial nodes are observed in I'm seeing radial nodes at
,
,
and
.
where represents the hydorgen bohr atomic radius = 0.0529177 nm
Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.
Answer:
Explanation:
We can use oxidation numbers to decide which substance is reduced.
The oxidation number of Na changes from 0 in Na to +1 in Na⁺.
The oxidation number of H changes from +1 in H₂O to 0 in H₂.
1 and 4 are wrong because H₂ and Na⁺ are products.
2. is wrong because there is no H⁺ to be oxidized or reduced.