Answer:
y = 11(x -1) +6
Step-by-step explanation:
The slope at the given point is ...
y' = 14x -3x^2 = 14(1) -3(1^2) = 11
Then the point-slope equation for the line can be written as ...
y = m(x -h) +k . . . . . . for slope m at point (h, k)
y = 11(x -1) +6
Equation: 7x - 3y = 21
3y = 7x - 21
Divide both sides by 3,
y = 7/3x - 7
Compare it with principle equation, y = mx + c
Here, slope (m) = 7/3
In short, Your Answer would be: 7/3
Hope this helps!
Extraneous root since dividing by zero is undefined