S = 10 + (-4) = 6
Displacement is vector quantity
Answer:
Explanation:
heat lost by coffee = heat gain by aluminum spoon
heat lost by coffee = mc ( 85° C - T)
175 ml of water = 175 grams
175 grams = (175 / 1000) kg = 0.175 kg
heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T
heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808
10.764 T - 236.808 = 62207.25 - 731.85 T
10.764 T + 731.85 T = 62207.25 + 236.808
T = 84.086 ° C approx 84°C
Solution:
Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg
Temperature = 200 °C
And 25% of the volume by liquid water is steam.
State 1
(taking the value of 
and at 200°C )
Now quality of vapor
Internal energy at state 1 can be found out by
= 856.54 kJ/kg
After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor 
Tank is rigid, so volume of tank is constant.
Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature
= 369.11° C
Internal energy at state 2
Now power rating of the resistor
= 1.51 kW
Answer:
YES
Explanation:
Gravity acts as the centripetal force and the velocity earth has keeps it from falling on the sun.
Answer:
-8.4°C
Explanation:
From the principle of heat capacity.
The heat sustain by an object is given as;
H = m× c× (T2-T1)
Where H is heat transferred
m is mass of substance
T2-T1 is the temperature change from starting to final temperature T2.
c- is the specific heat capacity of ice .
Note : specific heat capacity is an intrinsic capacity of a substance which is the energy substained on a unit mass of a substance on a unit temperature change.
Hence ; 35= 1× c× ( T2-(-25))
35= c× ( T2+25)
35 =2.108×( T2+25)
( T2+25)= 35/2.108= 16.60°{ approximated to 2 decimal place}
T2= 16.60-25= -8.40°C
C, specific heat capacity of ice is =2.108 kJ/kgK{you can google that}
