Answer:
f = 15 N
Explanation:
It is given that, when you push with a horizontal 15-N force on a book that slides at constant velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.
Need more than that to answer this question
Answer:
Approximately
.
Explanation:
The net force on the girl would be:
.
Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.
In other words, the tension force that the rope exerted on the girl would be
. The girl would exert a reaction force on the rope at the same magnitude (
) in the opposite direction. This force would translate to a
force on the boy towards the girl.
Under similar assumptions, the net force on the boy would also be
. Since the mass of the boy is
, the acceleration of the boy would be:
.
The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.
<h3>What is rest energy?</h3>
The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.
The rest energy is found as;

Convert into the mega electron volt;

Hence, the rest energy of the proton will be 938 MeV
To learn more about the rest energy, refer to the link;
brainly.com/question/15047418
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Answer:
Actually the formulae is S=(u+v/2)t
.TO explain,from average velocity=distance /time
and average velocity is u+v/2
hence using the formular
Average velocity=distance/time
distance will be=average velocity ×time
so S=(u+v/2)t