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d1i1m1o1n [39]
3 years ago
12

Deb drives 120 miles in 2 hours. What is her average speed

Physics
1 answer:
vladimir2022 [97]3 years ago
7 0
60 miles an hour because 120÷2=60
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Prentice Hall. All
iVinArrow [24]

Answer:

Decreases/Reduces

Explanation:

Fill in the blank:

Consider the equation Work = Force X Distance.

<em>If a machine  increases the distance over which a force is exerted, the force </em>

<em>required to do a given amount of work</em> .........

If the work is a constant value, then by isolating force from the equation, we get:

Force = Work / Distance

By increasing the value of the Distance, then the quotient Work. Distance diminishes, and therefore the required force decreases (diminishes, reduces)

Answer: Decreases/Reduces

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3 years ago
Fred is conducting a controlled experiment to test whether using a grow light at night will help a tomato plant grow faster. Bel
PtichkaEL [24]

Answer:

the type of tomato plants used.

Explanation:

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3 years ago
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

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\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

6 0
2 years ago
How do you find final speed of two objects that sticked together after colliding on an frictionless inclined plane?
Nady [450]

Explanation:

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2 years ago
A 100-g toy car moves along a curved frictionless track. At first, the car runs along a flat horizontal segment with an initial
Sholpan [36]

Answer:

2.994 m/s

Explanation:

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h = Height = 0.108 m

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We know that energy in the system is conserved so

\dfrac{1}{2}mv_1^2=mgh+\dfrac{1}{2}mv_f^2\\\Rightarrow v_f=\sqrt{2\left({\dfrac{1}{2}v_1^2-gh}\right)}\\\Rightarrow v_f=\sqrt{2\left(\dfrac{1}{2}3.33^2-9.81\times 0.108\right)}\\\Rightarrow v_f=2.994\ m/s

The final velocity of the car is 2.994 m/s

8 0
3 years ago
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