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vova2212 [387]
3 years ago
13

Please help me and get 15 points and Brainlessly!!!!!!!

Physics
1 answer:
aleksandrvk [35]3 years ago
4 0

Answer:

A

Explanation:

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A car sitting at a red light begins to accelerate at 2 m/s2 when the light turns green. It continues with this acceleration unti
jek_recluse [69]

Answer:

    x_total = 600 m

Explanation:

This is an exercise and kinematics, let's find the time it takes to reach the velocity  20 m / s

          v = v₀ + a t

           

as part of rest v₀ = 0

          t = v / a

          t = 20/2

          t = 10 s

let's find the distance traveled in this time

          x₁ = vo t + ½ a t2

          x₁ = 0 + ½ 2 10²

          x₁ = 100 m

The remaining time is

          t₂ = 35 - t

          t₂ = 35 - 10

          t₂ = 25 s

as in this range it has a constant speed

          v = x₂ / t₂

          x₂ = v t₂

          x₂ = 20  25

          x₂ = 500 m

the total distance traveled is

           x_total = x₁ + x₂

           x_total = 100 + 500

           x_total = 600 m

7 0
3 years ago
Which of these instruments can be used to peedict a thunderstorm?
FinnZ [79.3K]
<span> Doppler Radar is the instrument that is used to predict a thunderstorm. </span>
8 0
3 years ago
2. When the birth rate is larger than the death rate in any given period the population will
stich3 [128]
B if not please comment back .
8 0
3 years ago
an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
Juli2301 [7.4K]

Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

To Find :

the image height (in cm).

Solution :

By lens formula :

\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Here, u = - 100 cm

f =  150 cm

\dfrac{1}{v} - \dfrac{1}{-100} = \dfrac{1}{150}\\\\v = - 300 \ cm

Now, magnification is given by :

m = \dfrac{v}{u} = \dfrac{h_i}{h_o}\\\\h_i = \dfrac{300}{100}\times 1\\\\h_i = 3 \ m

Therefore, the image height is 3 m or 300 cm.

5 0
3 years ago
7.
kiruha [24]

Answer:

The given figure shows two men M and N facing two flat and hard walls, wall 1 and wall 2. Man N fires a gun. Man M hears two echoes, one from wall 1 and second from wall 2. The speed of sound in

air is given to be 325 m/s. After the firing of the gun by the man N, the man M will hear the first echo in how many seconds?

5 0
2 years ago
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