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diamong [38]
3 years ago
15

The diagram shows a ball falling toward Earth in a vacuum.

Physics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

c

Explanation:

murzikaleks [220]3 years ago
7 0

Answer: C

Explanation: I took the quiz on A p e x

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Along a horizontal snow-covered track, a sled, of mass m = 105 kg, slides by the action of a horizontal force of 230 N. The coef
Andrew [12]

Answer:

Explanation:

The only thing I can figure you need here is the accleration of the sled. The equation we need to find this is Newton's Second Law that says that sum of the forces acting on an object is equal to the object's mass times its acceleration. For us, that looks like this because of the friction working against the sled:

F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that

f = μF_n where μ is the coefficient of friction, and F_n is the normal force, aka weight of the object. We will use the coefficient of friction and find the weight in order to fill in for f:

F_n=mg so

F_n=(105)(9.8) so the weight of the sled is

F_n= 1.0 × 10³ with the correct number of sig dig there. Now to find f:

f = (.025)(1.0 × 10³) so

f = 25 to the correct number of sig fig. Now on to our "real" equation:

F - f = ma and

230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.

230 - 25 will round to the tens place giving us 210. Then

210 = 105a. 210 has 2 sig figs in it while 105 has 3, so we will divide and round to 2 sig fig:

a = 2.0 m/sec²

3 0
3 years ago
What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
lawyer [7]

I really think it could be a 23 kg

4 0
3 years ago
What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol
san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

Q=\frac{\Delta H}{n}

where,

Q = energy absorbed = 27.2 kJ

\Delta H = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

27.2kJ=\frac{6.01kJ/mol}{n}

n=0.221mol

Now we have to calculate the mass of ice.

\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}

Molar mass of ice = 18.02 g/mol

\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g

Thus, the mass of ice melted can be, 3.98 grams.

3 0
3 years ago
The lamp has a resistance of 10 ohms each resistor has a resistance of 10 ohms what is the total resistance of the circuit
prisoha [69]
Mark Brainliest please

Answer : if connected series, 20 ohms
And if connected parallel, answer will be less than 20 ohms

When resistors are wired in series, the total circuit resistance increases because each resistor contributes opposition to the circuit's current flow. Therefore if a 10 ohm resistor is placed in series with another 10 ohm resistor, the total resistance contributed by the two resistors is 20 ohms.
7 0
2 years ago
Humans sleep in cycles, usually two or three cycles per night. There is a point in each cycle when waking up will leave the slee
Mrrafil [7]
Hi hi I hope you know that you have a great time jaha
4 0
2 years ago
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