Ask question

Ask question

All categories

andrew-mc [135]

3 years ago

10

What metric unit would you use to estimate the actual distance between Boston and New York?

2 answers:

yarga [219]3 years ago

7 0

The answer to your question is meters.

MrMuchimi3 years ago

4 0

The metric unit of length and distance is the meter. Fractional parts
of it are used to describe very short distances, and multiples of it are
used to describe long ones. For distances by road, the kilometer is
widely used. That's a distance of 1,000 meters.

You might be interested in

Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the

Solnce55 [7]

Answer:

The combined speed of camper and canoe is 1.71 m/s.

Explanation:

Given that,

Mass of camper 1, m = 100 kg

Speed of camper 1, v = 3 m/s

The combined mass of another camper and canoe is, M = 175 kg

We need to find the combined speed of camper and canoe. According to the conservation of linear momentum, the momentum of first camper is equal to linear momentum of the canoe and the second camper.

$mv=MV\\\\V=\dfrac{mv}{M}\\\\V=\dfrac{100\times 3}{175}\\\\V=1.71\ m/s$

So, the combined speed of camper and canoe is 1.71 m/s.

4 0

3 years ago

Help me pls im sturgguleing in scince.

aliina [53]

A gas plasma i just took the quiz lol

8 0

2 years ago

Read 2 more answers

A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed

Katarina [22]

Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object $m_1=52 kg$

distance of $m_1$ from the axle $r_1=14 cm$

mass of rock $m_2=123 gm$

Length of rod $=4.1 m$

distance of $m_2$ from axle $r_2=4.1-0.14=3.96 m$

Net torque acting is

$T_{net}=m_1gr_1-m_2gr_2$

$T_{net}=52\times 0.14\times g-0.123\times 3.96\times g$

$T_{net}=6.793\times 9.8$

$T_{net}=66.57 N-m$

Work done by $T_{net}$ is converted to rock kinetic Energy

thus

$T_{net}\times \theta =\frac{mv^2}{2}$

Where $\theta =angle\ turned =\frac{\pi }{2}$

$v= velocity\ at\ launch$

$66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}$

$v^2=66.57\times \pi$

$v=\sqrt{1700.511}$

$v=41.23 m/s$

3 0

3 years ago

Please answer ASAP .

Arisa [49]

Answer:

Explanation:

a = gsinθ

a = 9.8sin30

a = 4.9 m/s²

v² = u² + 2as

v² = 0² + 2(4.9)(10)

v² = 98

v = √98 = 9.8994949...

v = 9.9 m/s

8 0

2 years ago

A car accelerate from a stop to 27 m/sec in 5 seconds. What was the car's acceleration?

Furkat [3]

The acceleration should 5.4 m/s^2

4 0

2 years ago