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Ulleksa [173]
2 years ago
11

25. a small container of water is placed on a turntable inside a microwave oven, at a radius of 12.0 cm from the center. the tur

ntable rotates steadily, turning one revolution in each 7.25 s. what angle does the water surface make with the horizontal?
Physics
1 answer:
Oksanka [162]2 years ago
4 0

The angle that the water surface make with the horizontal is 0.527°.

<h3>How to calculate the angles?</h3>

The water vapor moves at speed. Therefore,

v = 2πr/T = (2 × π × 0.120)/7.25

= 0.104m/s

Also, the top layer of water deals a downward force if gravity which will be:

= mv²/r = 0.104/0.12 = 0.0901

There, the angle will be:

= tan(0.0901/9.8)

= 0.527°

In this case, the angle that the water surface make with the horizontal is 0.527°.

Learn more about angles on:

brainly.com/question/25716982

#SPJ4

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IrinaVladis [17]

Answer:

5 minutes

Explanation:

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3 years ago
Boats use echo sounders. Pulses of sound waves are reflected by the sea bed and
Sati [7]

Answer: depth = 3.75 m

Explanation:

Taken the speed of the sound in sea to be V = 1500 m/s

The time between an echo sounder sending and receiving a pulse is 0.005 s. That is,

Total time T = 0.005

Formula for echo is:

V = 2X/T

Where X = distance covered

Substitute V and T into the formula

1500 = 2X/0.005

Cross multiply

7.5 = 2X

Make X the subject of formula

X = 7.5/2

X = 3.75 m

Therefore, the depth of the sea is 3.75 m

4 0
3 years ago
How do I do this problem?
Aleks04 [339]

Use Charles Law: V1/T1 = V2/T2

0.30 m^3/27 C = V2/127 C

27V2 = 127 * 0.3

V2= 38.1/27 = 1.4 m^3

5 0
3 years ago
A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta
larisa [96]

Answer:

Part a)

x = 15.76 m

Part b)

y = 7.94 m

Part c)

x = 26.16 m

Part d)

y = 7.49 m

Part e)

x = 83.23 m

Part f)

y = -75.6 m

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

v_x = 19.9 cos39.9

v_x = 15.3 m/s

similarly we have

v_y = 19.9 sin39.9

v_y = 12.76 m/s

Part a)

Horizontal displacement in 1.03 s

x = v_x t

x = (15.3)(1.03)

x = 15.76 m

Part b)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.03) - 4.9(1.03)^2

y = 7.94 m

Part c)

Horizontal displacement in 1.71 s

x = v_x t

x = (15.3)(1.71)

x = 26.16 m

Part d)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.71) - 4.9(1.71)^2

y = 7.49 m

Part e)

Horizontal displacement in 5.44 s

x = v_x t

x = (15.3)(5.44)

x = 83.23 m

Part f)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(5.44) - 4.9(5.44)^2

y = -75.6 m

6 0
3 years ago
Which is not a characteristic of a heat pump?
kramer
The answer is c. it requires no works
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3 years ago
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