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Ivahew [28]
3 years ago
8

Se lanza verticalmente hacia arriba un cuerpo que para por un punto A con una rapidez de 54 m/s y por otro punto B situado mas a

rriba con 24 m/s.calcular :a) tiempo en ir desde A hasta B;b )la altura vertical entre dichos puntos.
​
Physics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

a) 3,06 seg

b) 119,39 m

Explanation:

<u>Lanzamiento Vertical </u>

Cuando un cuerpo se lanza verticalmente hacia arriba en el vacío, la única fuerza actuante es el peso. Si asumimos la dirección negativa hacia abajo, las fórmulas necesarias son

v_f=v_o+gt

y=y_o+\frac{gt^2}{2}

v_f^2=v_o^2+2gy

Siendo v_f la velocidad final, y la altura del objeto, g=-9.8\ m/seg^2 , v_o la velocidad inicial y t el tiempo

a)

Sabemos que el cuerpo pasa por un punto A a v_o=54\ m/s, y por otro punto B más arriba, a v_f=24\ m/s. El cuerpo está subiendo, pues pierde velocidad. Sabiendo las dos velocidades, podemos calcular el tiempo que toma en ir de A a B

\displaystyle t=\frac{v_f-v_o}{g}

\displaystyle t=\frac{24-54}{-9.8}

\displaystyle t=\frac{-30}{-9.8}=3,06\ seg

b)

Conociendo las velocidades de los extremos, se encuentra la distancia vertical que recorre durante ese intervalo

v_f^2=v_o^2+2gy

\displaystyle 24^2=54^2+2(-9.8)y

\displaystyle 24^2-54^2=-19.6y

Despejando y

\displaystyle y=\frac{576-2916}{-19.6}

y=119,39\ m

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lora16 [44]

Answer:

Explanation:

The sun is made up of 6 parts. Namely:

  1. The core
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  4. The photosphere
  5. The chromosphere and
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The convection area is just above the radiation zone. As materials from the suns core are heated, they rise above the radiation zone towards the EDGE of the convection area then sinks back again into the radiative zone for more heat.

The radiative zone is 12.6 million Fahrenheit hot and is just above the core.

The core of the son is not solid but plasma whose motion is like gas. Its temperature stands at 48 million Fahrenheit

Cheers

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3 years ago
1.What do you think Sherman is right about?<br><br><br>2.What do you think Sherman is wrong about?
slamgirl [31]

Answer:

Sherman is right about the green used to camoflauge the dragonflies.

He is wrong about them being the **same** dragonflies.

8 0
3 years ago
While investigating Kirchhoff's Laws, you begin observing a blackbody, such as a star, from Earth using advanced technology that
Ksenya-84 [330]

Answer:

the second time there is a gas between you and the star,

Explanation:

When you observe the star for the first time you do not have a given between you and the star, therefore you observe the emission spectrum of the same that is formed by lines of different intensity and position that indicate the type and percentage of the atoms that make up the star.

 When you observe the same phenomenon for the second time there is a gas between you and the star, this gas absorbs the wavelengths of the star that has the same energies and the atomisms and molecular gas, therefore these lines are not observed by seeing a series of dark bands,

The information obtained from the two spectra is the same, the type of atoms that make up the star

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Varvara68 [4.7K]

Answer:

c. they travel through all forms of matter

Explanation:

3 0
3 years ago
a0.155 kg arrow is shot from ground level, upward at 31.4 m/s. what is its kinetic energy (ke) when it is 30.0 m above the groun
swat32

The kinetic energy (KE) of a 0.155 kg arrow that is shot from ground level, upward at 31.4 m/s, when it is 30.0 m above the ground is 30.85 J

Assuming air friction is negligible,

a = - 9.8 m / s²

u = 31.4 m / s

s = 30 m

v² = u² + 2 a s

v² = 31.4² + ( 2 * - 9.8 * 30 )

v² = 985.96 - 588

v² = 397.96 m / s

KE = 1 / 2 m v²

KE = 1 / 2 * 0.155 * 397.96

KE = 0.0775 * 397.96

KE = 30.85 J

Therefore, the kinetic energy ( KE ) when it is 30.0 m above the ground is 30.85 J

To know more about kinetic energy

brainly.com/question/24360064

#SPJ1

5 0
1 year ago
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