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Ivahew [28]
3 years ago
8

Se lanza verticalmente hacia arriba un cuerpo que para por un punto A con una rapidez de 54 m/s y por otro punto B situado mas a

rriba con 24 m/s.calcular :a) tiempo en ir desde A hasta B;b )la altura vertical entre dichos puntos.
​
Physics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

a) 3,06 seg

b) 119,39 m

Explanation:

<u>Lanzamiento Vertical </u>

Cuando un cuerpo se lanza verticalmente hacia arriba en el vacío, la única fuerza actuante es el peso. Si asumimos la dirección negativa hacia abajo, las fórmulas necesarias son

v_f=v_o+gt

y=y_o+\frac{gt^2}{2}

v_f^2=v_o^2+2gy

Siendo v_f la velocidad final, y la altura del objeto, g=-9.8\ m/seg^2 , v_o la velocidad inicial y t el tiempo

a)

Sabemos que el cuerpo pasa por un punto A a v_o=54\ m/s, y por otro punto B más arriba, a v_f=24\ m/s. El cuerpo está subiendo, pues pierde velocidad. Sabiendo las dos velocidades, podemos calcular el tiempo que toma en ir de A a B

\displaystyle t=\frac{v_f-v_o}{g}

\displaystyle t=\frac{24-54}{-9.8}

\displaystyle t=\frac{-30}{-9.8}=3,06\ seg

b)

Conociendo las velocidades de los extremos, se encuentra la distancia vertical que recorre durante ese intervalo

v_f^2=v_o^2+2gy

\displaystyle 24^2=54^2+2(-9.8)y

\displaystyle 24^2-54^2=-19.6y

Despejando y

\displaystyle y=\frac{576-2916}{-19.6}

y=119,39\ m

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