Answer:
At 81. 52 Deg C its resistance will be 0.31 Ω.
Explanation:
The resistance of wire =
Where 
=Resistance of wire at Temperature T
= Resistivity at temperature T ![=\rho_0 \ [1 \ + \alpha\ (T-T_0\ )]](https://tex.z-dn.net/?f=%3D%5Crho_0%20%5C%20%5B1%20%5C%20%2B%20%5Calpha%5C%20%28T-T_0%5C%20%29%5D)
Where 
l=Length of the wire
& A = Area of cross section of wire
For long and thin wire the resistance & resistivity relation will be as follows
![\frac{0.25}{0.31}=\frac{1}{[1+\alpha(T-20)]}](https://tex.z-dn.net/?f=%5Cfrac%7B0.25%7D%7B0.31%7D%3D%5Cfrac%7B1%7D%7B%5B1%2B%5Calpha%28T-20%29%5D%7D)
T = 81.52 Deg C
Answer:
Electric force, 
Explanation:
It is given that,
Charge on an electron is 
Electric field, 
We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :
So, the electric force is 
.
D. Unbalanced forces are acting on it.
hope this helped
Force = (mass) · (acceleration)
= (15 kg) · (8 m/s²)
= 120 kg-m/s² = 120 newtons
Answer:
5.67 x 10^ 1
Explanation:
Move the decimal once to the left
