If you apply an effort of 240N to a simple machine with a mechanical advantage of 3, what resistance force will the machine prod
1 answer:
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Complete Question:
A 58 kg box is at rest on a ramp, which is inclined 28° above the horizontal.The coefficient of static friction between the box and the ramp is 0.500. What is the magnitude of the minimum force, F, that must be applied to the box perpendicularly to the ramp to prevent the box from sliding?
Answer:
The minimum force required to prevent the box from sliding = 31.86N
Explanation:
mass of the box, m = 58 kg
θ = 28⁰
μ = 0.500
The normal reaction and the force preventing slide acts in the same direction.
The normal reaction,
Let the force preventing slide be
The net reaction R becomes,
The frictional force between the between the box and the ramp is:
..........(1)
To prevent the box from sliding, there must be equilibrium in the system
Sum of the vertical forces should be equal to the horizontal force
..............................(2)
Equating equations (1) and (2)