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3 years ago

Please help with this question

Physics

1 answer:

Gennadij [26K]3 years ago

3 0

Answer:

I believe the answer is 5718.75. Respond if it is wrong please.

Explanation:

I used a calculator.

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A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i

scoray [572]

Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

The initial height of the cliff

yo = 45m final, positition y = 0m bottom of the cliff

y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

0 = 45 +20t –4.9t²

Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

So this is the total time it takes for the ball to reach the ground from the height it was thrown.

The distance traveled by the woman is

s = vt

Given the speed of the woman v = 6.00m/s

Therefore

s = 6.00×5.69 = 34.14m

Approximately 34.1m to 3 significant figures.

3 0

3 years ago

A grinding wheel 0.35 m in diameter rotates at 2600 rpm .

ddd [48]

It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,

b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,

and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².

Calculation of angular velocity, linear speed & acceleration:

Provided that,

the diameter of the wheel = 0.35 m

So, the radius, r = 0.35/2 = 0.175 m

As 1 revolution = 2π rad

(a)the angular velocity, ω = 2600 rpm = $\frac{2600 * 2\pi }{60}$ rad/s

⇒ω = 272.13 rad/s

So, the angular velocity is 272.13 rad/s.

(b)The linear speed, v = r * ω

⇒v = 0.175 * 272.13

⇒v= 47.62 m/s

(c)The angular acceleration, $a=\frac{v^{2} }{r}$

$a = \frac{(47.62)^{2} }{0.175}$

⇒ $a$ = 12958.08 m/s²

Learn more about angular velocity here:

brainly.com/question/13649539

#SPJ1

6 0

2 years ago

A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of valu

ehidna [41]

Answer:5.21 N

Explanation:

Given

B=5.210 T

I=2 A

L=0.5 m

Given Wire is perpendicular to Magnetic field

$\theta =90^{\circ}$

$F=IL\times B$

$F=BIL sin\theta$

$F=5.210\cdot 2\cdot 0.5 sin(90)$

F=5.210 N

as 1 Tesla =1 N/A/m

4 0

3 years ago

When you and a friend move a couch to another room, you exert a force of 75 N over 5 m. How much work did you do?

bagirrra123 [75]

Answer:375J

Explanation:

Force=75N

Distance=5m

Work=force x distance

Work=75 x 5

Work=375J

5 0

3 years ago

Determine the inductive reactance for a 50 mH inductor that is across a 15 volt, 400 Hz source.

tresset_1 [31]

Answer:

Inductive reactance is 125.7 Ω

Explanation:

It is given that,

Inductance, $L=50\ mH=0.05\ H$

Voltage source, V = 15 volt

Frequency, f = 400 Hz

The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :

$X_L=2\pi fL$

$X_L=2\pi \times 400\ Hz\times 0.05\ H$

$X_L=125.66\ \Omega$

$X_L=125.7\ \Omega$

So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.

8 0

3 years ago