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mojhsa [17]
3 years ago
10

Circuit A in a house has a voltage of 208 V and is limited by a 40.0-A circuit breaker. Circuit B is at 120.0 V and has a 20.0-A

circuit breaker. What is the ratio of the maximum power delivered by circuit A to that delivered by circuit B
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Given Information:  

Voltage of circuit A = Va = 208 Volts

Current of circuit A = Ia = 40 Amps

Voltage of circuit B = Vb = 120 Volts

Current of circuit B = Ib = 20 Amps

Required Information:  

Ratio of power = Pa/Pb = ?

Answer:  

Ratio of power = Pa/Pb = 52/15

Explanation:  

Power can be calculated using Ohm's law

P = VI

Where V is the voltage and I is the current flowing in the circuit.

The power delivered by circuit A is

Pa = Va*Ia

Pa = 208*40

Pa = 8320 Watts

The power delivered by circuit B is

Pb = Vb*Ib

Pb = 120*20

Pb = 2400 Watts

Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is

Pa/Pb = 8320/2400

Pa/Pb = 52/15

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We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:

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s= \frac{1}{2}(u+v)t
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Since we have u, a, t and we want v
We will use the first formula v=u+at

v=1.6+(0.33)(3.6)
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3 years ago
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LiRa [457]

The horizontal speed of the object 1.0 seconds later is 1) 5.0 m/s.

Explanation:

The motion of an object thrown horizontally off a cliff is a projectile motion, which follows a parabolic path that consists of two independent motions:

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Since in this case the object has been launched with a horizontal speed of

v = 5.0 m/s

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Learn more about projectile motion:

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Disagree.
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3 years ago
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irinina [24]

Answer:

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Explanation:

From the question,

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I = m×v................... Equation 1

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