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2 years ago

Newton’s 3rd law is also known as the law of

Physics

1 answer:

NemiM [27]2 years ago

6 0

Answer:

Action and Reaction

Explanation:

For every force, there is one of equal and opposite also. Think of it this way. When you try to push on a wall, you are applying a force. However, that wall is also pushing back on you with that same force. You can also see this when you high five someone. You can slap as hard as you want to their stationary hand, but due to the 3rd law, you're both going to be left with red hands do to the amount of force applied.

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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre

Igoryamba

Answer:

a) $\frac{F_1}{L}=1.95*10^-^5N$

b) $\frac{F_2}{L}=1.95*10^-^5N$

Explanation:

From the question we are told that:

Distance between wires $d=32.2$

Wire 1 current $I_1=2.75$

Wire 2 current $I_2=4.33$

Generally the equation for Force on $l_1$ due to $I_2$ is mathematically given by

$F_1=I_1B_2L$

Where

B_2=Magnetic field current by $I_2$

$B_2=\frac{\mu *i_2}{2\pi d}$

Therefore

$F_1=I_1B_2L$

$F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L$

$\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }$

$\frac{F_1}{L}=1.95*10^-^5N$

Generally the equation for Force on $I_2$ due to $I_1$ is mathematically given by

$F_2=I_2B_1L$

Where

B_1=Magnetic field current by $I_2$

$B_1=\frac{\mu *I_1}{2\pi d}$

Therefore

$\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})$

$\frac{F_2}{L}=1.95*10^-^5N$

5 0

2 years ago

Amy needs 5.0 V for some integrated circuit experiments. She uses a 9.0 V battery and two resistors to make a voltage divider. O

just olya [345]

Answer:

The value of smaller resistor is 248 Ω.

Explanation:

Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.

As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.

Applying KVL in the circuit, the output voltage is given by :

$V_{0} = \frac{V_{s}R_{2} }{R_{1} + R_{2} }$

According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.

$5 = \frac{9\times310 }{R_{1} + 310 }$

$R_{1}+310 = \frac{9\times310}{5}$

$R_{1} = 558 - 310$

R₁ = 248Ω

7 0

3 years ago

The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert

zimovet [89]

Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

$F=\dfrac{mv^2}{r}$