Question

Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.

Answer 1

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  $H_2C_2O_4$

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

$H_2C_2O_4(aq)+H_2O(l) \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)$

Now the elimination of other proton

$HC_2O_4^-(aq)+H_2O(l) \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)$