Answer: A golfer hitting a golf ball.
Explanation:
The atomic particles move more in this option than the others.
99% of the filtrate's water that enter bowman's capsule is reabsorbed into the blood. This is because the water and the salts contained in the filtrate are needed for optimal functioning of the body system.
In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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In group theory, a branch of mathematics, the term order is used in two unrelated senses:
<span><span>The order of a group is its cardinality, i.e., the number of elements in its set. Also, the order, sometimes period, of an element a of a group is the smallest positive integer m such that <span>am = e</span> (where e denotes the identity element of the group, and am denotes the product of m copies of a). If no such m exists, a is said to have infinite order.</span><span>The ordering relation of a partially or totally ordered group.</span></span>
This article is about the first sense of order.
The order of a group G is denoted by ord(G) or | G | and the order of an element a is denoted by ord(a) or | a |.
Answer:
- 1 is the correct option
Explanation:
In determining the oxidation state or formal charge on element in an ionic specie, the whole ion need to be equated to the value of charge on the ion.
For example in this case, the charge on the ion is -3. Thus; representing iodine with X and putting -2 for the oxidation state of O (oxygen)
X + -2 = -3 (adding 2 to both side)
X = -3 + 2
X = - 1
