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geniusboy [140]
3 years ago
10

An aerosol can contains 800.0 mL of compressed gas at 10.2 atm pressure. When the gas is sprayed into a large plastic bag, the b

ag inflates to a volume of 4.14 L. What is the pressure of gas (atm) inside the plastic bag if the temperature did not change and all of the gas was transferred completely?
Chemistry
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

The pressure of the gas inside the plastic bag is 1.971 atm

Explanation:

Since temperature did not change, it means it is constant. This will then be Boyle's law. Thus

P1V1 =P2V2

Where P1 is the initial pressure = 10.2 ATM, P2 is the final pressure which is to be calculated.

V1 is the initial volume = 800.0 mL and V2 is the final volume of the gas = 4.14 L

From the formula,

P2 = P1V1/V2

= 10.2×800÷4.14

= 1.971 atm

Klio2033 [76]3 years ago
5 0

Answer:

Pressure of gas in the plastic bag is 1.97 atm

Explanation:

It is possible to answer this question by using Boyle's law: Boyle's law describes that, for ideal gases, the pressure of the gas is inversely proportional to the volume it occupies. Is expressed as:

P1V1 = P2V2

Where:

P1 is the initial pressure of the gas (In the problem, 10.2 atm).

V1 is initial volume (800.0mL)

V2 is final volume (4.14L ≡ 4140mL)

And P2 is the final pressure.

Replacing:

10.2 atm×800.0mL = 4140mL×P2

<em>P2 = 1.97 atm</em>

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VladimirAG [237]

<u>Given:</u>

Mass of calcium nitrate (Ca(NO3)2) = 96.1 g

<u>To determine:</u>

Theoretical yield of calcium phosphate, Ca3(PO4)2

<u>Explanation:</u>

Balanced Chemical reaction-

3Ca(NO3)2 + 2Na3PO4 → 6NaNO3 + Ca3(PO4)2

Based on the reaction stoichiometry:

3 moles of Ca(NO3)2 produces 1 mole of Ca3(PO4)2

Now,

Given mass of Ca(NO3)2 =  96.1 g

Molar mass of Ca(NO3)2 =  164 g/mol

# moles of ca(NO3)2 = 96.1/164 = 0.5859 moles

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Molar mass of Ca3(PO4)2 = 310 g/mol

Mass of Ca3(PO4)2 produced = 0.0196 * 310 = 6.076 g

Ans: Theoretical yield of Ca3(PO4)2 = 6.08 g



7 0
3 years ago
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maria [59]

Answer:

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Explanation:

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2 years ago
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Explanation:

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