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geniusboy [140]
3 years ago
10

An aerosol can contains 800.0 mL of compressed gas at 10.2 atm pressure. When the gas is sprayed into a large plastic bag, the b

ag inflates to a volume of 4.14 L. What is the pressure of gas (atm) inside the plastic bag if the temperature did not change and all of the gas was transferred completely?
Chemistry
2 answers:
Roman55 [17]3 years ago
5 0

Answer:

The pressure of the gas inside the plastic bag is 1.971 atm

Explanation:

Since temperature did not change, it means it is constant. This will then be Boyle's law. Thus

P1V1 =P2V2

Where P1 is the initial pressure = 10.2 ATM, P2 is the final pressure which is to be calculated.

V1 is the initial volume = 800.0 mL and V2 is the final volume of the gas = 4.14 L

From the formula,

P2 = P1V1/V2

= 10.2×800÷4.14

= 1.971 atm

Klio2033 [76]3 years ago
5 0

Answer:

Pressure of gas in the plastic bag is 1.97 atm

Explanation:

It is possible to answer this question by using Boyle's law: Boyle's law describes that, for ideal gases, the pressure of the gas is inversely proportional to the volume it occupies. Is expressed as:

P1V1 = P2V2

Where:

P1 is the initial pressure of the gas (In the problem, 10.2 atm).

V1 is initial volume (800.0mL)

V2 is final volume (4.14L ≡ 4140mL)

And P2 is the final pressure.

Replacing:

10.2 atm×800.0mL = 4140mL×P2

<em>P2 = 1.97 atm</em>

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w = -2740.16 J

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<u>Step 2:</u> Calculate work done

For ideal gases ΔU depends only on temperature. So as it is an isothermal (T constant).

Since the temperature remains constant:

ΔU = 0

ΔU = q + w

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⇒ with R = the gas constant = 8.314 J/mol*K

⇒ with T = the temperature = 300 Kelvin

⇒ with Pi = the initial pressure = 3.00 atm

⇒ with Pf = the final pressure = 1.00 atm

w =- 1*8.314 *300 * ln(3)

w = -2740.16 J

q = -w

q = 2740.16 J

<u>Step 3:</u> Calculate change in enthalpy

Since there is no change in energy, ΔH = 0

<u>Step 4:</u> Calculate ΔS

for an isothermal process

ΔS (total) = ΔS(sys) + ΔS(surr)  

ΔS(sys) = -ΔS(surr)

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<u>Step 1</u>: Calculate the work done

w = -Pext*ΔV

w = -Pext*(Vf - Vi)

⇒ with Vf = the final volume

⇒ with Vi = the initial volume

We have to calculate the final and initial volume. We do this via the ideal gas law P*V=n*R*T

V = (n*R*T)/P

Initial volume = (n*R*T)/Pi

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Final volume = (n*R*T)/Pf

     ⇒ Vf = (1*0.08206 *300)/1

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The work done w = -Pext*(Vf - Vi)

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ΔS(surr) = -1662.9J/300K

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