Using Mirror equation A, Calculate The Frequency Of The Long Stand And The Shortest Wave Length Of That An Object Is Placed Of A
1 answer:
The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;
The magnification of the lens is found as;
Hence, the image distance and magnification of The image will be 30 cm and 3.
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Answer:
a = - 11.53[m/s^2]
Explanation:
The airplane slows down as its speed decreases from the initial value of 610 [m/s] to zero.
To calculate the acceleration value we use the following kinematics equation:
where:
Vf = final velocity = 0
Vi = initial velocity = 610 [m/s]
a = acceleration [m/s2]
t = time = 53 [s]
Now replacing:
0 = 610 + (a*53)
-610 = 53*a
a = - 11.53[m/s^2]
The negative sign means that the aircraft is losing speed, i.e. slowing down