Question

Using Mirror equation A, Calculate The Frequency Of The Long Stand And The Shortest Wave Length Of That An Object Is Placed Of A Distance 10Cm From The Concave Mirror radius of Current Tube 30 Cm Find the Image distance and Magnification of The Image ​

Answer 1

The Image distance and Magnification of The Image ​will be 30 cm and 3.

What is focal length?

The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.

Given data;

Focal length,f=?

Image distance,v=?

Object distance,u= 10 cm

Magnification,m= 2.85

The focal length is half of the radius;

f=R/2

f=30 Cm/2

f= 15 Cm

The mirror equation is found as;

$\rm \frac{1}{f} =\frac{1}{v} +\frac{1}{u} \\\\\ \frac{1}{15}=\frac{1}{v}+\frac{1}{10} } \\\\\ v= -30 \ cm$

The magnification of the lens is found as;

$\rm m=\frac{30}{10}\\\\ m=3$

Hence, the image distance and magnification of The image ​will be 30 cm and 3.

To learn more about the focal length refer;

brainly.com/question/16188698

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