How much work did the movers do (horizontally) pushing a 41.0-kg crate 10.6 m across a rough floor without acceleration, if the
effective coefficient of friction was 0.60?
1 answer:
Answer:
The required work done is
Explanation:
Consider 'F' is the applied force on the crate and 'f' be the force created by friction. According to the figure if '' be the coefficient of friction, then
where 'M', 'N' and 'g' are the mass of the crate, the normal force aced upon the block and the acceleration due to gravity respectively.
Since the application of force by the movers does not create any acceleration to the block, we can write
So the work done (W) in moving the crate by a distance s = 10.6 m is
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a) , 1.6 A
b) , 1.33 A
Explanation:
a)
In this situation, we have two resistors connected in series.
The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:
where
Therefore, the equivalent resistance is
Now we can use Ohm's Law to find the current flowing through the circuit:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance of the circuit
Substituting,
The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.
b)
In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is
where:
Substituting, we find the equivalent resistance:
Now we can find the current through the circuit by using again Ohm's Law:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance
Substituting,
And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.