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3 years ago

13

If 1.0 joule of work is required to move a charge of 1.0 coulomb between two points is an electric field the potential differenc

e between these two point is?

1 answer:

deff fn [24]3 years ago

6 0

Answer:1V

Explanation: simply put it

V=W/q

=1/1

=1V

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Answer:

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Explanation:

Information we have:

velocities:

initial velocity: $v_{i}=0mph$ (starts from rest)

final velocity: $v_{f}=50mph$

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Since we need the answer in $m/s^2$ , we nees to convert the speed to meters per second:

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We find the acceleration with the following formula:

$a=\frac{v_{f}-v_{i}}{t}$

substituting the known values:

$a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2$

the acceleration is 10.07 $m/s^2$

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