If 1.0 joule of work is required to move a charge of 1.0 coulomb between two points is an electric field the potential differenc
1 answer:
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Answer:
The current is reduced to half of its original value.
Explanation:
- Assuming we can apply Ohm's Law to the circuit, as the internal resistance and the load resistor are in series, we can find the current I₁ as follows:
- where Rint = r and RL = r
- Replacing these values in I₁, we have:
- When the battery ages, if the internal resistance triples, the new current can be found using Ohm's Law again:
- We can find the relationship between I₂, and I₁, dividing both sides, as follows:
- The current when the internal resistance triples, is half of the original value, when the internal resistance was r, equal to the resistance of the load.
Answer:
The capillary rise of the glycerin is most nearly
Explanation:
From the question we are told that
The diameter of the glass tube is
The density of glycerin is
The surface tension of the glycerin is
The capillary rise of the glycerin is mathematically represented as
substituting value
Therefore the height of the glass tube the glycerin was able to cover is