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Nuetrik [128]
3 years ago
10

A 13.6 kg block is tied at the top of an incline to a tree. If the incline is 35.5 degrees and the coefficient of friction betwe

en the sled and the incline is .45, What is the tension force between the block and the tree
Physics
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

Explanation:

ASSUMING that block = sled AND that the rope is parallel to the slope.

The force acting parallel due to the weight is

13.6(9.81)sin35.5 = 77.475 N

The maximum friction force is

(0.45)13.6(9.81)cos35.5 = 48.877 N

If rope tension is T

77.475 - 48.877 < T < 77.475 + 48.877

            28.6 N < T < 126 N

28.6 N will occur if the block is on the verge of sliding downhill

126 N will occur if the block is on the verge of sliding uphill

Could be any value between them.

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Describe the principle of conversation of energy:
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What quantity of heat is needed to convert 1 kg of ice at -13 degrees C to steam at 100 degrees C?
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Heat energy needed = 3036.17 kJ

Explanation:

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     heat of vaporization of water = 2257 J/g

     specific heat of ice = 2.09 J/g·°C

     specific heat of water = 4.18 J/g·°C

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Here wee need to convert 1 kg ice from -13°C to vapor at 100°C

First the ice changes to -13°C from 0°C , then it changes to water, then its temperature increases from 0°C to 100°C, then it changes to steam.

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Heat energy required to change water temperature from 0°C to 100°C  

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Total heat energy required

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Heat energy needed = 3036.17 kJ

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