Answer:
Explanation:
Given data:
Thickness of aluminium sheet 10 cm
initial temperature = 25 degree celcius
Assumption
Thermal properties remain constant, transfer of heat by radiation is negligible.
from the information given in the question we have
T_S ≈T_∞ , it implies we have h → ∞
from table 4.2 Biot number → ∞ the value of
The fourier number is
Temperature at center after 15 second of heating
The average acceleration of the cheetah is 7.75 m/s²
The given parameters;
velocity of the cheetah, v = 31 m/s
time of motion, t = 4 seconds
The average acceleration of the cheetah is calculated as follows;
where;
v is the final velocity
u is the initial velocity
t is the time of motion
Assuming the cheetah started from rest, the initial velocity, u = 0
The average acceleration is calculated as follows;
Thus, the average acceleration of the cheetah is 7.75 m/s²
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Answer:
The intensity of light passing from the third polarizer is 3Io/16.
Explanation:
The law of Malus is given by
Let the incident intensity of light is Io.
The intensity of light passing from the first polarizer is
The intensity of light passing from the second polarizer is
The intensity of light passing from the third polarizer is