Answer:
Explanation:
- We have to make a hollow sphere of inner radius
and outer radius 
.
Then the mass of the material required to make such a sphere would be calculated as:
Total volume of the spherical shell:
And the volume of the hollow space in the sphere:
Therefore the net volume of material required to make the sphere:
- Now let the density of the of the material be
.
<u>Then the mass of the material used is:</u>
Answer:
a = Δv/t = (vf - vi)/t = (0 - 5)/4 = -1.25 m/s²
Explanation:
You may or may not need the negative sign, depending on how the question designer was thinking about the problem.
Answer: Here this will help you..
Explanation:
1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second
5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second
10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second
20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second
30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second
40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second
50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second
75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second
100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second
When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to contract in size. The gravitational forces becomes strong and cause the star to reduce in size. as the star contracts, the temperature of the star also rises since the heat is distributed inside smaller Volume now.
