Answer:
pH = 6.82
Explanation:
To solve this problem we can use the<em> Henderson-Hasselbach equation</em>:
- pH = pKa + log
![\frac{[NaOCl]}{[HOCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl%5D%7D%7B%5BHOCl%5D%7D)
We're given all the required data to <u>calculate the original pH of the buffer before 0.341 mol of HCl are added</u>:
- pKa = -log(Ka) = -log(2.9x10⁻⁸) = 7.54
- [HOCl] = [NaOCl] = 0.500 mol / 0.125 L = 4 M
- pH = 7.54 + log

By adding HCl, w<em>e simultaneously </em><u><em>increase the number of HOCl</em></u><em> and </em><u><em>decrease NaOCl</em></u>:
- pH = 7.54 + log
![\frac{[NaOCl-HCl]}{[HOCl+HCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl-HCl%5D%7D%7B%5BHOCl%2BHCl%5D%7D)
- pH = 7.54 + log

Answer:
The density of the liquid in beaker B is less than the that of ice.
Explanation:
Ice will float if its mass is less than the mass of the liquid it displaces.
For example, the density of ice is less than that of water.
A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.
The denser water displaces the lighter ice and the ice floats to the top.
If the density of the liquid is <em>less than</em> that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.

Then, 


The reaction is as bellows:

1 mole
reacts with 1 mole 
Therefore,
Then, unreacted

Volume of the solution = 
Now, molar concentration of 

completely dissociates in solution.
Therefore,![[NaOH]=[[OH-]=7.46×10^-4 moles/L](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5B%5BOH-%5D%3D7.46%C3%9710%5E-4%20moles%2FL)
![pOH= -log[OH-]= -log(7.46×10^-4)= 3.12](https://tex.z-dn.net/?f=pOH%3D%20-log%5BOH-%5D%3D%20-log%287.46%C3%9710%5E-4%29%3D%203.12)
Again,
or,

<h3> </h3><h3>
If sodium hydroxide were added to a solution of strong acid, what would happen to the pH of the solution?</h3>
Depending on how much
is added, yes. The solution has a pH of 7 if the amount of additional
is exactly equal to the amount of acid.
Since
is an excess reagent, the solution will become basic if more equivalents of base are added than equivalents of acid, and the pH of the solution will rise above 7.
The solution will be acidic, with a pH lower than 7, if the number of equivalents of acid exceeds that of the
that has been added.
To learn more about Sodium hydroxide,visit:
brainly.com/question/20371039
#SPJ4
Answer:
4.16M/s
Explanation:
Based on the reaction:
CH₄ + N₂Cl₄ ⇄ CCl₄ + N₂ + 2H₂
1 mole of methane, CH₄, produce 2 moles of H₂.
That means whereas 1 mole of methane is consumed, 2 moles of H₂ are formed
Having this in mind, if you are consuming methane at a rate of 2.08M/s, the rate of formation of hydrogen must be twice this rate, because there are produced twice moles of H₂.
Thus, rate of formation of H₂ is:
2.08M/s ₓ 2 =
4.16M/s