Answer:
0.0375 moles HBr
Explanation:
we are given;
- Molarity of HBr solution as 0.15 M
- Volume of the solution as 250 mL
We are required to determine the number of moles;
We need to know that;
Molarity = Moles ÷ Volume
Therefore;
Moles of HBr = Molarity of HBr solution × Volume of solution
Thus;
Moles of HBr = 0.15 M × 0.25 L
= 0.0375 Moles
Thus, the number of moles of HBr solute is 0.0375 moles
Answer:
The equilibrium concentration of NO is 0.02124 M.
Explanation:
Given that,
Initial concentration of NOBr = 0.878 M

Temperature = 24°C
We know that,
The balance equation is

Initial concentration is,

Concentration is,

Equilibrium concentration

We need to calculate the value of x
Using formula of concentration
![k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}](https://tex.z-dn.net/?f=k_%7Bc%7D%3D%5Cdfrac%7B%5BNO%5D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E2%7D)
Put the value into the formula
![3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}](https://tex.z-dn.net/?f=3.07%5Ctimes10%5E%7B-4%7D%3D%5Cdfrac%7B%5B2x%5D%5Bx%5D%7D%7B%5B0.878-2x%5D%5E2%7D)





We need to calculate the equilibrium concentration of NO
Using formula of concentration of NO

Put the value of x


Hence, The equilibrium concentration of NO is 0.02124 M.
True if im wrong u can take away my points
Answer:
0.18 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm, R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.8316×5.3)/(0.083×295)
n = 0.18 moles
<h3>
Answer:</h3>
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
Salt formed is LiCl
<h3>
Explanation:</h3>
- Arrhenius acid refers to a substance that ionizes in water to generate protons or hydrogen ions.
- Examples of Arrhenius acid include acids such as HCl, H₂SO₄ and HNO₃.
- A reaction between Lithium hydroxide and an Arrhenius acid such as HCl will yield a salt and water.
That is;
LiOH(aq) +HCl(aq)→ LiCl(aq) + H₂O(l)
- The salt formed is LiCl
- The reaction is an example of neutralization reaction.