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vitfil [10]
4 years ago
12

A sample of 0.900 mol N2O is placed in a sealed

Chemistry
1 answer:
Anettt [7]4 years ago
8 0

Answer:

  • <u>t = 284 min (rounded to 3 significant figures).</u>

Explanation:

<u>1. Decomposition reaction:</u>

Chemical equation:

  • 2N₂O → 2N₂ + O₂

<u>2. First order reaction:</u>

Rate law:

r=-\frac{d[N_2O]}{dt}= k[N_2O]\\ \\ \frac{d[N_2O]}{dt}= -k[N_2O]

Integrated rate law:

\frac{d[N_2O]}{[N_2O]}=-kdt\\ \\ ln[N_2O]-ln[N_2O]_0=-kt

<u>3. Determine the rate constant, k</u>

  • t = 42.0 min, [N₂O] = 0.640 mol

  • [N₂O]₀ = 0.900

  • ln(0.640)-ln(0.900)=-k(42.0min)

  • k = 0.00812 min⁻¹

<u>4. Time taken for the reaction to be 90.0% complete</u>

  • [N₂O] = 0.100[N₂O]=0.100×0.900 mol = 0.0900 mol

  • ln(0.0900) - ln(0.900) = - 0.00812 min⁻¹ × t

  • t = (2.30 / 0.00812) min ≈ 283.6 min ≈ 284 min (rounded to 3 significant figures).
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