Answer:
Yes. I think the answer is yes
The standard form of the quadratic equation is given by:
ax ^ 2 + bx + c
What we must do in this case is to rewrite the given equation.
We have then:
2/3 (x-4) (x + 5) = 1
(x-4) (x + 5) = 3/2
(x ^ 2 + 5x-4x-20) = 3/2
2x ^ 2 + 2x-40 = 3
2x ^ 2 + 2x-43 = 0
Thus, the values of a, b and c are:
a = 2
b = 2
c = -43
Answer:
a = 2
b = 2
c = -43
Answer:
13
Step-by-step explanation:
f(x) = 3x + 7
f(2) = 3(2) + 7
f(2) = 6 + 7
f(2) = 13
Just set up a proportion
(2/3)=(x/24)
cross multiply both sides
24(2)=3(x)
then solve
48=3x
x=48/3
x=16
16 is the correct answer
Because z is the unknown that we need to find, we treat t and a as constants (or numbers).
a(t+z)= 45z+67
⇒ at+ az= 45z+ 67 (distributive property)
⇒ at- 67= 45z- az
⇒ at- 67= z(45- a) (distributive property)
⇒ (at -67)/ (45- a)= z
Final answer: z= (at- 67)/ (45- a)
Hope this helps.
