Answer:
On a coordinate plane, a triangle has points (negative 4, 3), (negative 4, negative 2), (1, negative 2).
Step-by-step explanation:
The points (-4,3), (1,2) and (-4, -2) would form a right triangle when graphed and connected by lines.
(-4,3), (1,2) and (1,3) would also work as well
Answer:
Is there a diagram to this question?
Step-by-step explanation:
We could use the formula, derive the formula, or just work it out for this case. Let's do the latter.
The distance of a point to a line is the length of the perpendicular from the line to the point.
So we need the perpendicular to 5x-4y=10 through (-1,3). To get the perpendicular family we swap x and y coefficients, negating one. We get the constant straightforwardly from the point we're going through:
4x + 5y = 4(-1)+5(3) = 11
Those lines meet at the foot of the perpendicular, which is what we're after.
4x + 5y = 11
5 x - 4y = 10
We eliminate y by multiplying the first by four, the second by five and adding.
16x + 20y = 44
25x - 20y = 50
41x = 94
x = 94/41
y = (11 - 4x)/5 = 15/41
We want the distance from (-1,3) to (94/41,15/41)
Answer:
s = -3
Step-by-step explanation:
1 = 4s + 13
rewrite
4s + 13 = 1
4s = 1 - 13
4s = -12
s = -3
Answer: that’s complicated ;-;
Step-by-step explanation: