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1 year ago

I need helpppppp!!!!!!!!

Mathematics

1 answer:

kirill115 [55]1 year ago

6 0

Hello, I’m not super sure about the last part but to get 1 divide 20 by 20 and then from 1 multiply by 12 to get 12. I hope this helps :)

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2x² + 3x - 1 =0 by make quadratic equation

Strike441 [17]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

1/2

5 0

2 years ago

If triangle ABC with vertices A(-2, -5), B(-3, 2), and C (1, -2) a right triangle?

V125BC [204]

Hello :
A(-2, -5), B(-3, 2), and C (1, -2)
calculate : AB² , AC² ,BC²
 AB² = ( -3 +2 )² + ( 2 +5 )² =50
AC² = ( 1 +2 )² + ( -2 +5 )² =18
BC² = ( 1 +3 )² + ( -2 - 2 )² = 32
by petagor rule : AB² = AC² + BC²....(ABC is a right triangle in : C )

7 0

3 years ago

Sherry needs to have at least $1600 in her bank account at the end this month. She works at a restaurant where she earns $18 an

o-na [289]

Answer: 100 hours

Step-by-step explanation:

She has to get a total of 1800 dollars. Since she works 18 dollars an hour, divide 1800 and 18.

1800/18 = 100 hours

3 0

3 years ago

Allison buys a spool of thread for sewing. There are 8 yards of thread on the spool. She uses 1 meter. How much thread is left o

Rus_ich [418]

Thread left on the spool in meters is 6.3152 meter (Approx.)

Given that;

Total spool = 8 yards

Allison used = 1 meter of spool

Find:

Thread left on the spool in meters

Computation:

Total spool = 8 yards

Total spool in meter = 8 × 0.9144

Total spool in meter = 7.3152 meter (Approx.)

Thread left on the spool in meters = Total spool in meter - Allison used

Thread left on the spool in meters = 7.3152 - 1

Thread left on the spool in meters = 6.3152 meter (Approx.)

Learn more:

brainly.com/question/24129078?referrer=searchResults

8 0

2 years ago

Here are Xavier's bowling scores:

sammy [17]

Answer:

The variance rounded to the nearest tenth is 691.8

Step-by-step explanation:

Xavier's bowling scores:

135, 140, 130, 190, 112, 200, 185, 172, 163, 151, 149

No. of observations n = 11

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{135+140+130+190+112+200+185+172+ 163+ 151+149}{11}\\Mean =157$

Formula of variance : $\sigma^2=\frac{\sum(x_i-\bar{x})^2}{n}$

$\sigma^2=\frac{(135-157)^2+(140-157)^2+(130-157)^2+(190-157)^2+(112-157)^2+(200-157)^2+(185-157)^2+(172-157)^2+(163-157)^2+(151-157)^2+(149-157)^2}{11}$

$\sigma^2=\frac{7610}{11}$

$\sigma^2=691.81$

Hence the variance rounded to the nearest tenth is 691.8

6 0

2 years ago