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2 years ago

Which benefit outweighs the risks in the technological design of headphones?

2 answers:

8 0

The advantages of the technical design of headphones that can block out distractions outweigh the hazards. Option C is correct.

<h3>What is headphone?</h3>

A user wears headphones, which are a pair of miniature loudspeaker speakers, on or near their head over their ears.

They function as electroacoustic transducers, converting an electrical signal into an associated sound.

This capability is included on the majority of headphones, particularly over-ear and in-ear monitors.

They are intended to cover your ears with padding to form an airtight seal that cancels and muffles outside noise. Consider the sound that is produced when your hands are over your ears.

The benefit that outweighs the risks in the technological design of headphones is that they can eliminate distractions.

Hence option C is correct.

To learn more about the headphone refer to:

brainly.com/question/10714699

#SPJ1

scoray [572]2 years ago

5 0

Answer:

They can eliminate distractions

Explanation:

because I got it correct

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HELP HELP in order for energy to transform it must be able to do what?

pantera1 [17]

Answer:

1 thermal to nuclear to mechanical to electrical. 2 thermal to mechanical to nuclear to electrical. 3 nuclear to mechanical to electrical to thermal. 4 nuclear to thermal to mechanical to electrical.

5 0

3 years ago

A NASA explorer spacecraft with a mass of 1,000 kg takes off in a positive direction from a stationary asteroid. If the velocity

Jet001 [13]

Before the launch, the momentum of the (spacecraft + asteroid) was zero. So after the launch, the momentum of the (spacecraft + asteroid) has to be zero.

Momentum = (mass) x (velocity)

Momentum after the launch:

Spacecraft: (1,000 kg) x (250 m/s) = 250,000 kg-m/s

Asteroid: (mass) x (-25 m/s)

Their sum: 250,000 - 25(mass) .

Their sum must be zero, so 250,000 kg-m/s = (25 m/s) x (mass)

Divide each side by 25 : 10,000 kg-m/s = (1 m/s) x (mass)

Divide each side by (1 m/s) : 10,000 kg = mass

3 0

3 years ago

Read 2 more answers

A 2.0-kg object moving 5.0 m/s collides with and sticks to an 8.0-kg object initially at rest. Determine the kinetic energy lost

densk [106]

Answer:

20J

Explanation:

In a collision, whether elastic or inelastic, momentum is always conserved. Therefore, using the principle of conservation of momentum we can first get the final velocity of the two bodies after collision. This is given by;

m₁u₁ + m₂u₂ = (m₁ + m₂)v ---------------(i)

Where;

m₁ and m₂ are the masses of first and second objects respectively

u₁ and u₂ are the initial velocities of the first and second objects respectively

v is the final velocity of the two objects after collision;

From the question;

m₁ = 2.0kg

m₂ = 8.0kg

u₁ = 5.0m/s

u₂ = 0 (since the object is initially at rest)

<em>Substitute these values into equation (i) as follows;</em>

(2.0 x 5.0) + (8.0 x 0) = (2.0 + 8.0)v

(10.0) + (0) = (10.0)v

10.0 = 10.0v

v = 1m/s

The two bodies stick together and move off with a velocity of 1m/s after collision.

The kinetic energy(KE₁) of the objects before collision is given by

KE₁ = $\frac{1}{2}$ m₁u₁² + $\frac{1}{2}$ m₂u₂² ---------------(ii)

Substitute the appropriate values into equation (ii)

KE₁ = ( $\frac{1}{2}$ x 2.0 x 5.0²) + ( $\frac{1}{2}$ x 8.0 x 0²)

KE₁ = 25.0J

Also, the kinetic energy(KE₂) of the objects after collision is given by

KE₂ = $\frac{1}{2}$ (m₁ + m₂)v² ---------------(iii)

Substitute the appropriate values into equation (iii)

KE₂ = $\frac{1}{2}$ ( 2.0 + 8.0) x 1²

KE₂ = 5J

The kinetic energy lost (K) by the system is therefore the difference between the kinetic energy before collision and kinetic energy after collision

K = KE₂ - KE₁

K = 5 - 25

K = -20J

The negative sign shows that energy was lost. The kinetic energy lost by the system is 20J

3 0

4 years ago

According to the formula for stopping distance, how many feet will it take you to stop, from 60 mph?

myrzilka [38]

Answer:

534 ft

Explanation:

given,

speed of the vehicle = 60 mph

1 mph = 0.447 m/s

60 mph = 60 x 0.447 = 26.82 m/s

stopping distance = ?

Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.

Reaction time of a common person = 1.5 s

taking coefficient of friction of the road = 0.3

using equation of stopping sight distance

S.D = RD + BD

RD is Reaction distance

RD = v t_r

RD = 26.82 x 1.5

RD = 40.23 m

BD is the braking distance

$BD = \dfrac{v^2}{2\mu g}$

$BD = \dfrac{26.82^2}{2\times 0.3\times 9.8}$

BD = 122.33 m

Stopping sight distance

SD = 40.23 + 122.33

SD = 162.56 m

1 m = 3.28 ft

162.56 m = 162.56 x 3.28

= 533.20 ft ≈ 534 ft

hence, the stopping distance will be equal to 534 ft

8 0

3 years ago

Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

$q = \lambda * L$

$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

Now using the above formula

$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

8 0

3 years ago