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2 years ago

Which benefit outweighs the risks in the technological design of headphones?

2 answers:

8 0

The advantages of the technical design of headphones that can block out distractions outweigh the hazards. Option C is correct.

<h3>What is headphone?</h3>

A user wears headphones, which are a pair of miniature loudspeaker speakers, on or near their head over their ears.

They function as electroacoustic transducers, converting an electrical signal into an associated sound.

This capability is included on the majority of headphones, particularly over-ear and in-ear monitors.

They are intended to cover your ears with padding to form an airtight seal that cancels and muffles outside noise. Consider the sound that is produced when your hands are over your ears.

The benefit that outweighs the risks in the technological design of headphones is that they can eliminate distractions.

Hence option C is correct.

To learn more about the headphone refer to:

brainly.com/question/10714699

#SPJ1

scoray [572]2 years ago

5 0

Answer:

They can eliminate distractions

Explanation:

because I got it correct

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<h2>a</h2><h2> move with an increasing velocity</h2>

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3 years ago

Select whether the argument is an example of a deductive or an inductive argument:

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3 years ago

A two-stage rocket moves in space at a constant velocity of +4300 m/s. The two stages are then separated by a small explosive ch

ololo11 [35]

Answer:

$v_{1f}$ = +3,394 103 m / s

Explanation:

We will solve this problem with the concept of the moment. Let's start by defining the system that is formed by the complete rocket before and after the explosions, bone with the two stages, for this system the moment is conserved.

The data they give is the mass of the first stage m1 = 2100 kg, the mass of the second stage m2 = 1160 kg and its final velocity v2f = +5940 m / s and the speed of the rocket before the explosion vo = +4300 m / s

The moment before the explosion

p₀ = (m₁ + m₂) v₀

After the explosion

pf = m₁ $v_{1f}$ + m₂ $v_{2f}$

p₀ = [texpv_{f}[/tex]

(m₁ + m₂) v₀ = m₁ $v_{1f}$ + m₂ $v_{2f}$

Let's calculate the final speed (v1f) of the first stage

$v_{1f}$ = ((m₁ + m₂) v₀ - m₂ $v_{2f}$ ) / m₁

$v_{1f}$ = ((2100 +1160) 4300 - 1160 5940) / 2100

$v_{1f}$ = (14,018 10 6 - 6,890 106) / 2100

$v_{1f}$ = 7,128 106/2100

$v_{1f}$ = +3,394 103 m / s

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3 years ago

Explain why the top of the loop cannot be the same height as (or higher than) the top of the first hill. Assume the roller coast

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Answer:

By conservation of energy, it can climb up to a height equal to that it went down before. However, due to the friction in the machines, the total mechanical energy of the roller coaster will decrease. As a result, the first "hill" of many roller coasters are the highest, but the followings will have decreasing heights.

Explanation:

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2 years ago

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